Understanding Moment of Inertia for a Box: Calculations and Examples

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The discussion focuses on calculating the moment of inertia for a box with dimensions a, b, and c, and mass M. The user seeks assistance in understanding the calculations for two specific axes: one through the center and perpendicular to the faces of sides a and b, and another along an edge of length c. A response emphasizes the need for clarification and encourages the user to show their work to identify where they are struggling. The moment of inertia is defined as the integral of the squared distance from the axis of rotation, multiplied by density, over the volume of the box. The complexity arises from the box's lack of circular symmetry, necessitating careful setup of the coordinate system for accurate calculations.
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I'm really having problems understanding how to do moment of inertia. Can someone please help me with this problem? Explain it to me please. Thanks so much.

Question:

Find the moment of inertia of a box of sides a, b, and c, mass M, and uniform density for rotations about an axis passing through its center and perpendicular to the two faces of sides a and b.

Find the moment of inertia for rotations about an axis passing along one edge of length c.
 
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please help me

will someone please help?
 
I think this question sounds a little vague. Can you clairfy it a little better?

Also, show some work that you have done so we can see where you are having trouble. That will also help us (atleast me) visualize what is going on.
 
The "moment of inertia" of an object around an axis of rotation is the integral of (distance of each point from the axis of rotation)2 times the density. The integral is taken over the volume of the object. The fact that this is not circularly symmetric makes it a little harder. Take the (uniform) density to be the constant δ Set up a coordinate system so that center of one "a by b" face is at (0,0,0) and the center of the other face is at (0,0,c). Then the distance from a point (x,y,z) to the nearest point on the axis of rotation, (0, 0, z), is &radic:(x2+ y2and its square is, of course, simply x2+y2. The moment of inertia is:
\int_{x=-a/2}^{a/2}\int_{y=-b/2}^{b/2}\int_{z=0}^{c} \delta(x^2+ y^2)dzdydx
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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