High School Understanding Planes and Tetrahedrons

  • Thread starter Thread starter LogarithmLuke
  • Start date Start date
  • Tags Tags
    Planes Tetrahedron
Click For Summary
SUMMARY

The discussion centers on the geometric principles governing the formation of tetrahedrons using vectors. It is established that three vectors lying in the same plane cannot form a tetrahedron, as the height is zero, regardless of the plane's orientation. The cross product of vectors AB and AC is confirmed to be perpendicular to both, and checking if this cross product is perpendicular to vector AD determines if all four points A, B, C, and D lie in the same plane. Additionally, while two of the three vectors can lie in the same plane, this does not contribute to the formation of a tetrahedron.

PREREQUISITES
  • Understanding of vector mathematics and properties
  • Familiarity with cross product and dot product operations
  • Knowledge of geometric concepts related to planes and tetrahedrons
  • Basic grasp of linear algebra and vector spaces
NEXT STEPS
  • Study the properties of vector cross products in detail
  • Learn about the geometric interpretation of dot products
  • Explore the concept of vector spaces and their dimensions
  • Investigate the conditions for coplanarity of points in three-dimensional space
USEFUL FOR

Students of mathematics, physics enthusiasts, and professionals in engineering or computer graphics who require a solid understanding of vector geometry and its applications in three-dimensional space.

LogarithmLuke
Messages
82
Reaction score
3
Hi, I am having trouble understanding why three vectors that lie in the same plane can't form a tetrahedron. If the plane is somewhat vertical or titlted will it not be possible for one vector to higher up than another so that you have a difference in height? Also, for three vectors to form a tetrahedron, can two of the vectors lie in the same plane?

Additionally, if given 4 points, A,B,C,D and you want to check if the points all lie in the same plane. How come it works to check if the crossproduct between vectors AB and AC is perpendicular to vector AD? (i.e finding the crossproduct between vectors AB and AC and then finding the dot product between that and vector AD and seeing if it equals zero).

Any help is appreciated. Please don't hesitate to ask if you need me to clear up on something regarding the questions.
 
Mathematics news on Phys.org
Try to draw a proper tetrahedron on paper. It does not matter how you hold that paper in your room: it does not work.

If your third vector is in the plane formed by the other two, the height of your "tetrahedron" is zero, which means you don't have a tetrahedron. This is independent of the orientation of this plane in space.

LogarithmLuke said:
How come it works to check if the crossproduct between vectors AB and AC is perpendicular to vector AD?
What do you know about the cross product of AB and AC? How is that property, and vectors orthogonal to this cross product, related to the previous part of your post?
 
mfb said:
What do you know about the cross product of AB and AC? How is that property, and vectors orthogonal to this cross product, related to the previous part of your post?

The cross product of vectors AB and AC must be perpendicular to both AB and AC. So does that mean vector AD is also perpendicular to AB and AC as its perpendicular to the cross product between them? Or is it that the only way for vector AD to be perpendicular to the cross product of vectors AB and AC is if AB, AC and AD all lie in the same plane?
 
LogarithmLuke said:
So does that mean vector AD is also perpendicular to AB and AC as its perpendicular to the cross product between them?
No. Apart from its length, the cross product of AB and AC is the only vector that is perpendicular to both. If AD is perpendicular to AB and perpendicular to AC, then it has to be parallel to the cross product.
LogarithmLuke said:
Or is it that the only way for vector AD to be perpendicular to the cross product of vectors AB and AC is if AB, AC and AD all lie in the same plane?
This is correct. The cross product is perpendicular to the plane of AB and AC. Every vector perpendicular to that cross product is in the plane.
 
mfb said:
No. Apart from its length, the cross product of AB and AC is the only vector that is perpendicular to both. If AD is perpendicular to AB and perpendicular to AC, then it has to be parallel to the cross product.
This is correct. The cross product is perpendicular to the plane of AB and AC. Every vector perpendicular to that cross product is in the plane.

I understand it a lot better now, thank you.

Was it true that two of the three vectors forming a tetrahedron can be in the same plane, though?
 
LogarithmLuke said:
I understand it a lot better now, thank you.

Was it true that two of the three vectors forming a tetrahedron can be in the same plane, though?
Yes, although this is trivially true. Any two vectors lie in the same plane.

Take one of the two vectors, and move it so that its tail coincides with the tail of the other vector. If the two vectors are parallel (or antiparallel -- i.e., point in opposite directions), they lie along some line in the plane. This includes the possibility that one of the vectors is the zero vector. (If both vectors are zero vectors, then all you have is a single point in the plane.)

If the two vectors point in different directions, the tails of the two vectors are at one point, and the heads of the vectors are at two other points, giving use three distinct points, and thereby defining a plane.
 
Mark44 said:
Take one of the two vectors, and move it so that its tail coincides with the tail of the other vector.
Moving vectors doesn't really make sense in mathematics. Vectors do not have a "location".
 
mfb said:
Moving vectors doesn't really make sense in mathematics. Vectors do not have a "location".
Fine, but I think you are being pedantic. We can call them directed line segments that extend from some initial point to a terminal point. A directed line segment like this is considered equivalent to a vector extending from the origin, if the vector and the directed line segment have the same length and direction.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
5K
Replies
9
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K