Understanding Planetary Motion: Correcting a Common Misconception

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
mormreed
Messages
2
Reaction score
0
I just need an explanation of a formula, and I think part of it is wrong, so here is the formula:

[tex](T_A/T_G)^2=(R_A/R_B)^3[/tex]


so T is the period and [tex]T_A[/tex] is the period of planet A
then below it is what I think is wrong, [tex]T_G[/tex] G is the Kepler's constant, I'm not sure what that really is
=
[text]R_A[/tex] which is radius of planet A over radius of planet B cubed, this side is right, any help is appreciated thanks
 
Physics news on Phys.org
I comes from Kepler's third law which states that

[tex]T^2 \propto R^3[/tex]


So if two planets have the same mass, in your case planet A and G.

then [itex]T_A^2= k R_A^3[/itex] and [itex]T_G^2= kR_G^3[/itex]

so just divide them and you'll get the formula
 
I think I found the answer after some searching, which I did try before which brought me here, but I think it is [tex](T_A/T_B)^2=(R_A/R_B)^3[/tex]