Understanding Quantum Computing: Unanswered Questions

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The discussion centers on the complexities of quantum computing as outlined in Seth Lloyd's "Programming the Universe." Key points include the unique nature of quantum parallelism, where quantum bits (qbits) can perform multiple tasks simultaneously through interference. However, several critical questions remain unanswered, such as how quantum computers execute multiplication for specific qbit tasks, the mechanism of interference between successful and failed trials, and how they determine task completion. The conversation also references recent experiments demonstrating Shor's algorithm for factoring numbers, highlighting ongoing research in the field. Overall, the need for clearer explanations of these fundamental concepts in quantum computing is emphasized.
MikeFromOhio
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I've been reading "Programming the Universe" by Seth Lloyd, a quantum computer scientist. He goes on and on about the power of quantum computers and their ability, for example, to factor large numbers using massive parallelism. He also states that quantum parallelism is different than classical parallelism. In the quantum case, he says, the individual quantum bits (or qbits) are interfering with each other which is helpful.

A quantum computer of 4 qbits, he says, can be carrying out 2**4 or 16 tasks simultaneously. So if your trying to factor the number 20, one task might be trying out 6*3 which does not equal 20 while another task might be trying 4*5 which does.

What he does not explain is:

1) How does the Quantum Computer carry out the multiplication for a given qbit task?

2) If interference is important, then how do the separate trials interfere which each other? And how do failed tasks (6*3) interfere with the tasks which are successful (4*5) ?

3) How does the Quantum Computer know when it is done?

Any feedback on these questions would be appreciated.
Thanks,
Mike
 
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Here's a report of an actual experiment last year which used Shor's algorithm to factor 15:

http://arxiv.org/abs/0911.1242

http://physicsworld.com/cws/article/news/40306
 
Unusualname, thanks for the links.
I can see that it's a bit hard to explain.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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