Understanding Solutions to 2x=x2

  • Thread starter Thread starter christian0710
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around the equation 2x = x² and the solutions x = 2 and x = 0. Participants explore the validity of both solutions and the implications of dividing by a variable.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the reasoning behind the existence of both solutions, particularly the validity of x = 0. They discuss the implications of dividing by a variable and the conditions under which solutions can be considered valid.

Discussion Status

There is an ongoing exploration of the relationship between the two solutions. Some participants express confusion about the distinction between the equations 2x = x² and x = 2, noting that they have different solution sets. Clarifications regarding the implications of division by zero have been raised, contributing to a deeper understanding of the problem.

Contextual Notes

Participants mention the need for both solutions in the context of finding upper and lower limits for integration, indicating a specific application of the solutions in a broader mathematical context.

christian0710
Messages
407
Reaction score
8
This may be a dumb question but if we have the equation 2x=x2 and we use algebra we get
2=x2/x ---> 2=x



How come the solution is x= 2 (obvious) AND x=0 (not so obvious for me)
 
Physics news on Phys.org
Clearly x=0 is a valid solution of the original equation. But the important lesson is that whenever you divide by an expression of unknown value (x in this case) you should bear in mind that division by zero is not a defined operation. The correct procedure is always to write "if (expression) is nonzero then ...".
 
I see so you obtain that if x=0 you get 2*0=^2 and that's why x=0 is an equation?
But if we started with the equation x=2, then i assume you can't say x=2 and x=0, is that correctly understood? I needed both solutions because i was finding the upper and lower limits for integration, but just confues about the fact that x=2 also has x=0 as solution.
 
christian0710 said:
I see so you obtain that if x=0 you get 2*0=^2 and that's why x=0 is an equation?
But if we started with the equation x=2, then i assume you can't say x=2 and x=0, is that correctly understood? I needed both solutions because i was finding the upper and lower limits for integration, but just confues about the fact that x=2 also has x=0 as solution.

Well doesn't 2x=x^2 ⇔0=x^2-2x ⇔ 0=x(x-2) ⇔x=0 or x=2 Is that clear now? It is pretty simple.
 
christian0710 said:
I see so you obtain that if x=0 you get 2*0=^2 and that's why x=0 is an equation?
If x = 0, you get 2*0 = 02, so x = 0 is a solution to the original equation.
christian0710 said:
But if we started with the equation x=2, then i assume you can't say x=2 and x=0, is that correctly understood?
The only possible replacement for x in the equation x = 2 is 2. That's the only value that makes the equation x = 2 a true statement.
christian0710 said:
I needed both solutions because i was finding the upper and lower limits for integration, but just confues about the fact that x=2 also has x=0 as solution.
The equation x = 2 does NOT have x = 0 as a solution. The equation 2x = x2 DOES have x = 0 (and x = 2) as a solution.

Since the equations x = 2 and 2x = x2 have different solution sets, they are not equivalent.
 
Thank you so much, now it's clear! Very clear :D
 
christian0710 said:
Thank you so much, now it's clear! Very clear :D

You're very welcome :D
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 24 ·
Replies
24
Views
4K
Replies
8
Views
5K
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K