kenok1216
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Homework Statement
Homework Equations
θmin=1.22λ/D
The Attempt at a Solution
(a)θmin=1.22λ/D
(b)θs=1.22(600nm)/30mm=24.4μm but what is spatial resolution and how to calculate it??
Understanding Spatial Resolution: Calculating and Applying θmin=1.22λ/D
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θmin=1.22λ/D
(a)θmin=1.22λ/D
(b)θs=1.22(600nm)/30mm=24.4μm but what is spatial resolution and how to calculate it??
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That answer should be in units appropriate for an angle, certainly not μm .kenok1216 said:
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It's related to the angular resolution. You can think of the spatial resolution as the arc length of a circle subtended by the angle of angular resolution.kenok1216 said:
kenok1216
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sor, it is μradSammyS said:
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Yes.kenok1216 said:
kenok1216
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s=rθ, so what is r is this question?object distance? focal length?image distance?blue_leaf77 said:
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About the circle I was talking about, you can assume it to be centered at the center of the lens and since your image is located at the focal plane, the arc length of interest must touch the focal plane. What will r be?kenok1216 said:
kenok1216
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Focal lenght?blue_leaf77 said:
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Yes.kenok1216 said:
kenok1216
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ThankSammyS said: