Understanding Tensors: Comparing gαβAβ and Aβgαβ

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Discussion Overview

The discussion revolves around the properties of tensor multiplication, specifically comparing expressions involving the metric tensor \( g_{\alpha\beta} \) and other tensors \( A \) and \( B \). Participants explore whether certain tensor products commute and the implications of tensor components versus full tensors.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether \( g_{\alpha\beta} A^{\beta} \) is the same as \( A^{\beta} g_{\alpha\beta} \).
  • Another participant asserts that \( g_{\alpha\beta} A^{\beta} \) and \( A^{\beta} g_{\alpha\beta} \) are indeed equal.
  • A further inquiry is made about the equality of \( B_{\alpha\beta} A^{\gamma} \) and \( A^{\gamma} B_{\alpha\beta} \), suggesting that the tensors \( A \) and \( B \) may not commute.
  • Some participants clarify that \( B_{\alpha\beta} \) represents components of a tensor, which are numbers and thus commute, while the full tensors must be treated differently.
  • There is a discussion about the representation of tensors and their components, with one participant noting that \( A_{\beta\alpha} B^{\gamma} \) can represent both the \( {}_{\beta\alpha}{}^{\gamma} \) component of the tensor \( A \otimes B \) and the \( {}^{\gamma}{}_{\beta\alpha} \) component of \( B \otimes A \).

Areas of Agreement / Disagreement

Participants express differing views on whether certain tensor products commute, indicating that the discussion remains unresolved with multiple competing perspectives on the properties of tensor multiplication.

Contextual Notes

There are limitations in the discussion regarding the assumptions about tensor components versus full tensors, and the implications of index notation are not fully resolved.

grzz
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I am learning about tensors.
Is gαβAβ the same as Aβgαβ ?
Thanks for any help.
 
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Yes.
 
But then is
BαβAγ equal to Aγ Bαβ ?
 
I think that the tensors A and B do not commute as the g and A do in the previous example. But I am not sure.
Any help!
 
grzz said:
But then is
BαβAγ equal to Aγ Bαβ ?
Bαβ is not tensor, it is the component of a tensor. The components of a tensor are real or complex numbers. They commute.
 
grzz said:
But then is
BαβAγ equal to Aγ Bαβ ?

As spyphy says this is just multiplication of numbers (components) so order doesn't matter. The full tensors must be formed by contracting the indices with basis elements. It is there where you see the distinctions in order written:
[itex]\mathbf{B}\otimes\mathbf{A}= B_{\alpha\beta} A^y \mathbf{e}^\alpha\otimes\mathbf{e}^\beta\otimes \mathbf{e}_y =A^y B_{\alpha\beta} \mathbf{e}^\alpha\otimes\mathbf{e}^\beta\otimes \mathbf{e}_y[/itex]
but note that:
[itex]\mathbf{B}\otimes\mathbf{A}= B_{\alpha\beta} A^y \mathbf{e}^\alpha\otimes\mathbf{e}^\beta\otimes \mathbf{e}_y \ne B_{\alpha\beta}A^y \mathbf{e}_y\otimes\mathbf{e}^\alpha\otimes\mathbf{e}^\beta = \mathbf{A}\otimes\mathbf{B}[/itex]
take your time parsing these and see the distinction.
 
Thanks for the help.
Since [itex]\alpha[/itex] is repeated in g[itex]_{}\beta_{}\alpha[/itex]A[itex]^{}\alpha[/itex] then it was clear to me that this is a sum and the g[itex]_{}\beta_{}\alpha[/itex] and the A[itex]^{}\alpha[/itex] are numbers and so commute.

But I thought that A[itex]_{}\beta_{}\alpha[/itex]B[itex]^{}\gamma[/itex] represented the product of two tensors. From the little I know I thought that sometimes a tensor is represented by one of its components. That is why I said that the second example may not commute.
 
I am also poor in using latex!
 
grzz said:
Thanks for the help.
Since [itex]\alpha[/itex] is repeated in g[itex]_{}\beta_{}\alpha[/itex]A[itex]^{}\alpha[/itex] then it was clear to me that this is a sum and the g[itex]_{}\beta_{}\alpha[/itex] and the A[itex]^{}\alpha[/itex] are numbers and so commute.

But I thought that A[itex]_{}\beta_{}\alpha[/itex]B[itex]^{}\gamma[/itex] represented the product of two tensors. From the little I know I thought that sometimes a tensor is represented by one of its components. That is why I said that the second example may not commute.
[itex]A_{\beta\alpha}B^\gamma[/itex] is equal to both the [itex]{}_{\beta\alpha}{}^\gamma[/itex] component of the tensor [itex]A\otimes B[/itex], and the [itex]{}^\gamma{}_{\beta\alpha}[/itex] component of the tensor [itex]B\otimes A[/itex].

Click the quote button if you want to see how I did the LaTeX. Try changing something and use the preview feature to see what it looks like. (To be able to preview, you need to trick the forum software into thinking that you're typing a reply, e.g. by typing at least 4 characters after the quote tags).
 
Last edited:
  • #10
Thank you because in those last four lines you gave me the best tutorial about LaTeX.
 

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