Understanding the Chain Rule for Partial Derivatives in Multivariable Calculus

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Somefantastik
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[tex]u^{*}(r^{*},\theta^{*},\phi^{*}) = \frac{a}{r^{*}}u(\frac{a^{2}}{r^{*}},\theta^{*},\phi^{*})[/tex]

[tex]\frac{\partial u^{*}}{\partial r^{*}}= \frac{a}{r^{*}}u_{r^{*}} \left( \frac{a^{2}}{r^{*}},\theta^{*},\phi^{*}\right) \left( -\frac{a^{2}}{r^{2*}} \right) - \frac{a}{r^{*2}} u \left( \frac{a^{2}}{r^{*}},\theta^{*},\phi^{*}\right)[/tex]

where [tex]u_{r^{*}}[/tex] is the partial of u w.r.t r*

Did I do this right? Is there a better way of representing [tex]u_{r^{*}} \left( \frac{a^{2}}{r^{*}},\theta^{*},\phi^{*}\right)[/tex]
 
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Somefantastik said:
[tex] Did I do this right? Is there a better way of representing [itex]u_{r^{*}} \left( \frac{a^{2}}{r^{*}},\theta^{*},\phi^{*}\right)[/itex][/tex]
[tex] <br /> Calculation is right but pedantically speaking you mean derivative of u with respect to its first argument which is a^2/r* not r*.<br /> <br /> I don't know what kind of notations mathematicians use for that, symbolic programs like Mathematica would denote it like Derivative[1,0,0]<u>.</u>[/tex]
 
well I'm trying to crank out the laplacian in spherical to show it u* is harmonic. So I'm just trying to differentiate with respect to each component and sub it into the laplacian in spherical and HOPEFULLY get zero.
 
I still need help with this. Is there anybody out there who can help me?