Understanding the chemical process in a fuel cell

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SUMMARY

This discussion focuses on the chemical processes involved in a one-compartment hydrogen peroxide (H2O2) fuel cell utilizing silver (Ag) foil as the anode and Prussian Blue as the cathode. The anode reaction produces oxygen and protons, while the cathode reaction reduces hydrogen peroxide to water, with Prussian Blue serving as a catalyst to lower the overpotential required for the reaction. The presence of Prussian Blue facilitates the cathodic reduction of H2O2, enhancing the fuel cell's efficiency by overcoming kinetic barriers associated with the reaction.

PREREQUISITES
  • Understanding of electrochemistry principles, particularly overpotential and activation barriers.
  • Familiarity with fuel cell components, specifically anodes and cathodes.
  • Knowledge of hydrogen peroxide chemistry and its reactions in acidic conditions.
  • Experience with catalysis, particularly the role of Prussian Blue in electrochemical reactions.
NEXT STEPS
  • Research the mechanisms of Prussian Blue as a catalyst in electrochemical applications.
  • Study the principles of overpotential and its impact on fuel cell efficiency.
  • Explore the design and optimization of one-compartment fuel cells.
  • Investigate the applications of hydrogen peroxide in biosensing and analytical chemistry.
USEFUL FOR

Students and professionals in energy science, electrochemistry researchers, and anyone interested in the development and optimization of fuel cell technologies.

JoJoQuinoa
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Hello,

I'm taking an energy class and I'll be giving a presentation on fuel cells. I was wondering if I could get some help understanding the whole process of the paper below. Unfortunately, I can't post the article because of copyrights. To summarize, it's a one compartment H2O2 fuel cell with Ag foil as the anode and Prussian Blue coated carbon paper as the cathode. The reaction is as follow:

Anode: H2O2 → O2 + 2H+ + 2e; Eo = −0.68 V
Cathode: H2O2 + 2H+ + 2e→ 2H2O ; Eo = 1.77 V
Total: 2H2O2 → 2H2O + O2

I am trying to understand the role of prussian blue in this setup. The paper mentioned that Prussian Blue acted as the catalyst for this reaction but I'm not sure which process they're referring to. Is the present of Prussian blue causes the H2O2 molecules to break down on the anode side or it is there to combine H2O2 with the ions to form water?

Thank you!

"A membraneless hydrogen peroxide fuel cell using Prussian Blue as cathode material"
 
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From the article:
Prussian Blue (PB) is a renowned catalyst for H2O2 reduction under acidic conditions and its electrocatalytic reduction of hydrogen peroxide for biosensing and analytical applications has been studied extensively.12,13

From reference #13:
242552

https://www.sciencedirect.com/science/article/pii/S0956566304005883?via=ihub
 
JoJoQuinoa said:
I am trying to understand the role of prussian blue in this setup.
Prussian blue catalyzes the cathodic reduction of hydrogen peroxide to water. Without a catalyst, there is a kinetic barrier to peroxide reduction (this is referred to as an overpotential in electrochemistry). The larger the overpotential, the less efficient the fuel cell is, because energy is “wasted” getting the peroxide reactants over the activation barrier.

Edit: strictly speaking, the overpotential refers to the excess amount of voltage you need (above the half-reaction potential) to actually get the reaction to proceed. It corresponds directly to the kinetic activation barrier of the reaction.
 

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