Understanding the Identity Operator in 2-Qubit Quantum Systems

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Discussion Overview

The discussion centers on the identity operator in 2-qubit quantum systems, specifically examining the unitary transformation associated with a 1-bit function and its implications for the identity operator. Participants explore the nature of the tensor product in quantum states and the appropriate categorization of the topic within quantum mechanics.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant proposes that the unitary transformation \mathbf{U}_f is defined as \mathbf{U}_f(\left| x\right>\left| y\right> )=\left| x\right>\left| y\oplus f(x)\right>, suggesting that x is the input register and y is the output register.
  • Another participant questions how \mathbf{U}_f can equal the identity operator \mathbf{1} when the function f is defined such that f(0)=0 and f(1)=0.
  • There is a query about whether \left| x\right>\left| y\right> represents a tensor product.
  • A participant asserts that \left| x\right>\left| y\right> indeed signifies a tensor product, indicating a common shorthand usage among practitioners.
  • One participant suggests that the discussion might be more appropriately categorized under "quantum mechanics."

Areas of Agreement / Disagreement

Participants express uncertainty regarding the implications of the unitary transformation and its relationship to the identity operator. There is also a lack of consensus on the categorization of the topic, with differing opinions on whether it fits better under quantum mechanics.

Contextual Notes

Participants do not clarify the assumptions underlying the definition of the unitary transformation or the tensor product, leaving some aspects of the discussion unresolved.

Dragonfall
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Suppose [tex]\mathbf{U}_f(\left| x\right>\left| y\right> )=\left| x\right>\left| y\oplus f(x)\right>[/tex] denotes the unitary transformation corresponding to some 1-bit function f.

I'm guessing here that x is the input register, and y the output register.

Now suppose f(0)=0 and f(1)=0.

How is it that [tex]\mathbf{U}_f=\mathbf{1}[/tex] the 2-Qbit unit operator?
 
Last edited:
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In general, is [tex]\left| x\right>\left| y\right>[/tex] a tensor product?
 
don't know about your first question but in general [tex]\left| x\right>\left| y\right>[/tex]
means tensor product, we are just too lazy to write it.
 
It might be better to post this under "quantum mechanics".
 

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