Understanding the math in the Michelson-Morley experiment

  • Thread starter Thread starter aj_17
  • Start date Start date
  • Tags Tags
    Experiment
Click For Summary
SUMMARY

The discussion centers on the mathematical interpretation of the Michelson-Morley experiment, specifically addressing the vector components of velocity in a scenario involving a swimmer crossing a river. The swimmer's effective velocity is calculated as sqrt(v2^2 - v1^2), where v2 is the swimmer's speed in still water and v1 is the river's current speed. The conversation highlights the importance of distinguishing between velocity as a vector and speed as its magnitude, emphasizing the need for clarity in problem phrasing. Participants are encouraged to represent velocities as vectors to solve the problem accurately.

PREREQUISITES
  • Understanding of vector mathematics and components
  • Familiarity with the concepts of speed and velocity
  • Basic knowledge of the Michelson-Morley experiment
  • Ability to apply algebra and trigonometry in physics problems
NEXT STEPS
  • Study vector addition and decomposition in physics
  • Learn about the implications of the Michelson-Morley experiment on modern physics
  • Explore the concepts of relative motion and reference frames
  • Practice problems involving velocities in different frames of reference
USEFUL FOR

Students of physics, educators teaching modern physics concepts, and anyone interested in the mathematical foundations of the Michelson-Morley experiment.

aj_17
Messages
2
Reaction score
1
[Mentors' note - No template because this post was moved from the Relativity forum]
Summary:: I'm trying to make sense of the trig/algebra in discussing the experiment. This is an excerpt from the textbook Modern Physics (Thornton/Rex) meant to further explain the set up, however I'm not following. Could someone explain this?

If a swimmer (who can swim with speed v2 in still water) wants to swim across a swiftly moving river (speed v1), the swimmer must start heading upriver, so that when the current carries her downstream, she will move directly across the river. Careful reasoning shows that the swimmer’s velocity is sqrt(v2^2-v1^2) throughout her journey (Problem 4).
 
Last edited by a moderator:
Physics news on Phys.org
The problem is a bit carelessly phrased because it's not respecting the distinction between velocity which is a vector, and speed, which is the magnitude of that vector, and because it's not being clear about which velocities are relative to what.

But with said, you'll be able to get through this problem if you write both the velocity of the water relative to the bank and the velocity of the swimmer relative to the water as vectors with components parallel to and perpendicular to the direction of the water flow. The swimmer's velocity relative to the bank (which is presumably what the problem is lookoing for, although it's not specified) is the sum of these two vectors.
 
This thread has been moved into the homework forum. You will have to show your work (there's a big hint in the previoius post) and say where you're getting stuck, and then we can help you over the hard spot
 

Similar threads

Replies
5
Views
8K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 47 ·
2
Replies
47
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
1
Views
2K