Understanding the Vector Triple Product Proof

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SUMMARY

The discussion centers on the proof of the vector triple product identity, specifically addressing the calculation of the constant ##\lambda##. It is established that setting ##\vec A = \vec C## does not lose generality, as ##\lambda## remains constant and independent of the vector choices. The conclusion emphasizes that since ##\lambda## equals one for a specific vector selection, it holds true universally across all vector combinations.

PREREQUISITES
  • Understanding of vector algebra and identities
  • Familiarity with the vector triple product
  • Basic knowledge of mathematical proofs
  • Experience with linear algebra concepts
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  • Study the derivation of the vector triple product identity
  • Explore the implications of constants in vector equations
  • Learn about the properties of linear transformations in vector spaces
  • Investigate other mathematical proofs involving vector identities
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This discussion is beneficial for students of mathematics, physics, and engineering, particularly those studying vector calculus and linear algebra. It is also useful for educators seeking to clarify concepts related to vector identities.

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Hello,

I am having trouble understanding a proof presented here:

http://www.fen.bilkent.edu.tr/~ercelebi/Ax(BxC).pdf

This is a proof of the triple product identity, but I don't understand the last step, where they calculate ##\lambda##. Don't you lose all generality when you state ##\vec A## equals ##\vec C##?

Thanks!
 
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No. You do not loose any generality. The number ##\lambda## is a constant that should be independent of what vectors you use. Hence, it is perfectly fine to use ##\vec A = \vec C##. When you do this you get a relation for ##\lambda##, but ##\lambda## is independent of what the vectors actually are. Hence, since it is equal to one for a particular choice of vectors, it must be equal to one for any choice of vectors.
 
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Ah I see, for some reason I interpreted the ##\lambda## to be dependent on the choice of vectors, but of course there is no reason for doing so. Thanks a lot!
 

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