Understanding Trajectory Graphs

  • Thread starter Thread starter mymabelline
  • Start date Start date
  • Tags Tags
    Graphs Trajectory
Click For Summary
SUMMARY

The discussion focuses on understanding trajectory graphs and their distinction from position vs. time graphs. It is established that the slope of a trajectory graph indicates the direction of velocity, but does not provide the actual velocity value. The equation for a trajectory graph is given as y = bx - ax², and differentiating this with respect to time yields the relationship between the rates of change of y and x, represented as dy/dt and dx/dt, both of which are velocities.

PREREQUISITES
  • Understanding of basic calculus, specifically differentiation.
  • Familiarity with kinematic equations and concepts of velocity and acceleration.
  • Knowledge of graphing quadratic functions and their properties.
  • Basic understanding of vector quantities in physics.
NEXT STEPS
  • Study the relationship between position, velocity, and acceleration in kinematics.
  • Learn how to differentiate functions to find rates of change in physics contexts.
  • Explore the concept of tangential velocity and its application in trajectory analysis.
  • Investigate the differences between scalar and vector quantities in motion analysis.
USEFUL FOR

Students studying physics, particularly those focusing on motion and kinematics, as well as educators looking to clarify the concepts of trajectory graphs and their applications.

mymabelline
Messages
7
Reaction score
0
Trajectory Graphs??

Homework Statement


The trouble I'm having is with determining what information I can get from a trajectory graph and how that information differs from what I can find on a position vs. time graph. Is the acceleration I find just the rate of change in the direction of velocity? and is the tangental velocity equal to speed or do we just we use it to represent the direction of velocity?




The Attempt at a Solution


The only thing that I think I know for sure is that the slope of the trajectory graph gives the direction of velocity, but not the actual velocity. But I don't know why that is true, my book does a horrible job of explaining that.
 
Physics news on Phys.org


You trajectory graph will be of the form y=bx-ax2.

So if you differentiate w.r.t t. you will get dy/dt = (b-2ax)dx/dt

dy/dt and dx/dt are both velocities, so you will get a velocity for the gradient.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
993
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
5
Views
1K
Replies
3
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K