Understanding Trig Notation: What Does Sin(90°-θ) Mean?

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Homework Help Overview

The discussion revolves around understanding the trigonometric notation Sin(90°-θ) and its relationship to other trigonometric functions, particularly in the context of acute angles and right-angled triangles.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the meaning of Sin(90°-θ) and its connection to cos(θ). There are attempts to relate the sine and cosine functions through the properties of right-angled triangles.

Discussion Status

Some participants have provided insights into the relationship between sine and cosine, particularly through the context of triangle geometry. There is an ongoing exploration of how to derive Sin(90°-θ) using similar reasoning.

Contextual Notes

Participants are focusing on acute angles and the properties of right-angled triangles, with some noting the importance of understanding the definitions of sine and cosine in this context.

Feodalherren
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I'm solving some trig functions and ran into a notation that says

Sin(90°-θ)

What does it mean?

I know what Sin θ is and I know that Sin 90° = 1.
 
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Just in case it's important, Sin θ=

(2x)(9+4x^2)^(1/2) / (9+4x^2)
 
Do you know how sin(90°-θ) is related to cos(θ)?

What is the full problem?

ehild
 
Feodalherren said:
I'm solving some trig functions and ran into a notation that says

Sin(90°-θ)

What does it mean?

I know what Sin θ is and I know that Sin 90° = 1.

θ is some angle (we'll only deal with acute angles here) and then sin θ is the ratio of the opposite side to the hypotenuse in a right-angled triangle with one of its angles as θ. But if you look at that same triangle, you can deduce that the last angle must be
180° - 90° - θ = 90° - θ
because a triangle's angles add up to 180o.
And now, what is the cosine of that angle? That is, what is cos (90° - θ)? Well, since cos of an angle is the ratio between the adjacent side and the hypotenuse, these are exactly the same sides in the ratio of sin θ, so that means that sin θ = cos (90° - θ)
Can you use a similar procedure to find out what Sin(90°-θ) is?
 

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