Need help solving this trig equation

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Homework Help Overview

The discussion revolves around solving the trigonometric equation 3cos(θ) + 1.595*sin(θ) = 3.114, with participants exploring various approaches and identities related to trigonometric functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the Pythagorean identity (sinθ)^2 + (cosθ)^2 = 1 to manipulate the equation. Some question the validity of the resulting values for cosθ, while others suggest alternative methods involving the transformation of the equation into a different form.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the correctness of certain steps. Some guidance has been offered regarding alternative approaches, but there is no explicit consensus on the best method to solve the equation.

Contextual Notes

There are constraints regarding the range of values for cosθ, as noted by participants, which impacts the validity of certain solutions. Additionally, the discussion includes references to specific trigonometric identities and transformations that may be relevant to the problem.

flgdx
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Homework Statement


what's the best way to solve this equation: 3cos(θ) + 1.595*sin(θ) = 3.114

Homework Equations


(sinθ)^2 + (cosθ)^2 = 1

The Attempt at a Solution


I tried using the identity above to solve this equation and ended up with cosθ = +/- 1.0526.
 
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Could you show your steps for your solution?
 
Comeback City said:
Could you show your steps for your solution?

so since (sinθ)^2 + (cosθ)^2 = 1, I solved for sinθ and got sqrt(1 - (cosθ)^2). Then I subtituted it into the equation 3cos(θ) + 1.595*sin(θ) = 3.114 and solved for θ.
 
flgdx said:

Homework Statement


what's the best way to solve this equation: 3cos(θ) + 1.595*sin(θ) = 3.114

Homework Equations


(sinθ)^2 + (cosθ)^2 = 1

The Attempt at a Solution


I tried using the identity above to solve this equation and ended up with cosθ = +/- 1.0526.
Well, that's obviously wrong because -1 ≤ cos θ ≤ 1, and 1.0526 is outside that range. Your approach should work though.

Another approach is to use
$$a \cos\theta + b \sin\theta = \sqrt{a^2+b^2} \cos(\theta-\phi)$$ where ##\tan\phi = b/a##.
 
could you pls show me how you got that equation?
 
Consider a right triangle below and use the identity ##\cos(\theta-\phi) = \cos\theta\,\cos\phi + \sin\theta\,\sin\phi##.

triangle.png
 

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