Understanding Vector Transformations: Problem 1

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Hi,

I am trying to follow an introductory problem in my book for which no solutions are provided and have got stuck. I was wondering whether anyone could tell me how to go about this problem and where I am going wrong.

The problem starts:

Consider the eqquations:
[tex]y_1= x_1+2x_2[/tex]
[tex]y_2=3x_2[/tex]

We can view these equations as describing a transformation of the vector x = [itex]\begin{bmatrix}x_1\\x_2\end{bmatrix}[/itex] into the vector y = [itex]\begin{bmatrix}y_1\\y_2\end{bmatrix}[/itex]

The transformation can be re-written as:

[tex]\begin{bmatrix}y_1\\y_2\end{bmatrix}=\begin{bmatrix}1 & 2\\0 & 3\end{bmatrix}\begin{bmatrix}x_1\\x_2\end{bmatrix}[/tex]

Or, more succinctly, y=Fx


Problem 1: Compute Fx For the following vectors x:

a) x=[itex]\begin{bmatrix}1\\1\end{bmatrix}[/itex] b) x=[itex]\begin{bmatrix}1\\-1\end{bmatrix}[/itex] c) x=[itex]\begin{bmatrix}-1\\-1\end{bmatrix}[/itex] d) x=[itex]\begin{bmatrix}-1\\1\end{bmatrix}[/itex]


My Results:

a) Fx=[itex]\begin{bmatrix}3\\3\end{bmatrix}[/itex] b) Fx=[itex]\begin{bmatrix}-1\\-3\end{bmatrix}[/itex] c) Fx=[itex]\begin{bmatrix}-3\\-3\end{bmatrix}[/itex] a) Fx=[itex]\begin{bmatrix}-1\\3\end{bmatrix}[/itex]


This is where I am unsure. The next step says "The heads of the four vectors x in problem 1 locate the four corners of a square in the [itex]x_1x_2[/itex] plane."

I'm not sure I understand this: what does the " [itex]x_1x_2[/itex] plane" mean? I would have thought it means a plane in which [itex]x_1[/itex] and [itex]x_2[/itex] are the axes... But I can't see how this can work as [itex]x_1[/itex] just consists of the points 3, -1,-3 and 1 on the x axis, as far as I can see...

I'd be very grateful if anyone could indicate where I'm going wrong..!
 
on Phys.org
[itex]x_1[/itex] and [itex]x_2[/itex] refer to your original vectors. The 4 points are [itex](\pm 1, \pm 1)[/itex]; these are the corners of a square.
 
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OK, thanks Chogg...
 

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