Understanding Wave-functions and Normalization?

In summary, the conversation discusses the concept of normalization in Quantum Mechanics and its relation to the probability of finding a particle in space. The square of the absolute value of the wave function represents the probability density of finding an electron in a specific location. For a particle to be considered real, it must be normalizable, meaning that the probability of finding it somewhere must be 1. This also means that the wave function cannot be zero for all values of x. The probability density at the origin can be determined using the given wave function and normalization constant.
  • #1
Quelsita
49
0
Question:

1. An electron is freely moving in a one‐dimensional coordinate,
x . At some point t in time, its (complex‐valued) wavefunction
is ψ (x,t) = Ceiωte−(x / a)2 .

a. Why must [tex]\int[/tex] [tex]\left|[/tex][tex]\Psi[/tex]|2=1?
b. From the so‐called normalization requirement given in
part a., determine the normalization constant C, assuming
it is a positive real number.
c. What is the unit of C in SI?
d. What is the probability density at the origin?


Basically right now I'm just trying to wrap my head around the concept of normalization etc but figured to list the whole problem to see where things were headed.
I get that the square of the absolute value of the wave function gives the probability density of finding a particle (in this case, an electron) in space.
And in Quantum Mechanics, all real particles must be "normalizable", meaning that the chance that said particle occupies some space must be 1. Is this just saying that for an electron in space, it has to be somewhere at sometime? That it simply can't NOT exist in space?
Also, must it only =1?
 
Physics news on Phys.org
  • #2
Quelsita said:
Basically right now I'm just trying to wrap my head around the concept of normalization etc but figured to list the whole problem to see where things were headed.
I get that the square of the absolute value of the wave function gives the probability density of finding a particle (in this case, an electron) in space.

To be more specific, in one-dimension [tex]|\psi(x)|^2[/tex] gives the probability that the particle is found in the interval from [tex]x[/tex] to [tex]x+d[/tex].

And in Quantum Mechanics, all real particles must be "normalizable", meaning that the chance that said particle occupies some space must be 1. Is this just saying that for an electron in space, it has to be somewhere at sometime? That it simply can't NOT exist in space?
Also, must it only =1?

If the quantum state is not such that the wavefunction is [tex]\psi(x)=0[/tex] for all [tex]x[/tex], then the probability of finding the particle somewhere cannot be zero. Said another way, the "no particle" state is the zero wavefunction.
 

1. What is a wave-function?

A wave-function is a mathematical description of the quantum state of a particle or system. It describes the probability of finding the particle in a particular state at a given time.

2. Why is normalization important in wave-functions?

Normalization is important because it ensures that the total probability of finding a particle in all possible states is equal to 1. This allows us to accurately interpret the wave-function as a probability distribution.

3. How is normalization achieved in wave-functions?

Normalization is achieved by dividing the wave-function by its integral, which is also known as the normalization constant. This ensures that the total probability of finding the particle in all possible states is equal to 1.

4. What are the physical implications of a normalized wave-function?

A normalized wave-function has physical implications in that it allows us to make accurate predictions about the behavior of quantum systems. It also ensures that the probabilities of finding a particle in different states are consistent with the principles of quantum mechanics.

5. Can a wave-function be normalized if it is complex?

Yes, a wave-function can still be normalized if it is complex. The normalization process involves taking the absolute value squared of the wave-function, which will result in a real number. Therefore, even if the original wave-function is complex, the normalized version will be real and fulfill the requirements of normalization.

Similar threads

  • Advanced Physics Homework Help
Replies
10
Views
444
  • Advanced Physics Homework Help
Replies
19
Views
454
  • Advanced Physics Homework Help
Replies
1
Views
923
Replies
16
Views
546
  • Advanced Physics Homework Help
Replies
8
Views
358
  • Advanced Physics Homework Help
Replies
3
Views
1K
  • Advanced Physics Homework Help
Replies
5
Views
986
  • Advanced Physics Homework Help
Replies
14
Views
876
  • Advanced Physics Homework Help
Replies
7
Views
980
  • Advanced Physics Homework Help
Replies
9
Views
1K
Back
Top