Understanding why cyclic rule works

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SUMMARY

The cyclic rule in partial derivatives states that for three variables x, y, and z, the relationship holds: (∂x/∂y)_z * (∂y/∂z)_x * (∂z/∂x)_y = -1. This negative sign arises from the rearrangement of the equation when considering the condition that dz = 0. The derivation of (∂x/∂y)_z involves finding the fraction dx/dy while holding z constant, leading to the conclusion that (∂x/∂y)_z = - (∂z/∂y)_x / (∂z/∂x)_y. Understanding these relationships is crucial for mastering the application of the cyclic rule in physical chemistry.

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  • Familiarity with the concept of holding variables constant in multivariable calculus
  • Basic knowledge of physical chemistry principles
  • Ability to manipulate mathematical equations involving derivatives
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  • Study the derivation of the cyclic rule in multivariable calculus
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gloryofgreece
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I don't quite understand why cyclic rule works (from Pchem)

(del x/ del y)_z = part of x with respect to y, hold z constant

I don't know why is it negative 1?

del x/ del y)_z * del y/ del z)_x * del z/ del x)_y = -1
 
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You could derive it. Not sure if there is any other way to imagine it
\mathrm{d}z=\left.\frac{\partial z}{\partial x}\right)_y\mathrm{d}x+\left.\frac{\partial z}{\partial y}\right)_x\mathrm{d}y
Now to get \left.\frac{\partial x}{\partial y}\right)_z from the above equation just find the fraction \frac{\mathrm{d}x}{\mathrm{d}y} under the condition that \mathrm{d}z=0, i.e.
\left.\frac{\partial x}{\partial y}\right)_z=\left.\frac{\mathrm{d} x}{\mathrm{d} y}\right)_{\mathrm{d}z=0}=-\frac{\left.\partial z/\partial y\right)_x}{\left.\partial z/\partial x\right)_y}
The minus sign comes from rearranging the first equation.

Also
\left.\frac{\partial z}{\partial y}\right)_x=\frac{1}{\left.\frac{\partial y}{\partial z}\right)_x}
or
\left.\frac{\partial z}{\partial y}\right)_x\left.\frac{\partial y}{\partial z}\right)_x=1
The apparent cancellation is only possible since both derivatives have the same variables kept constant!
 

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