Understanding WKB Approximation for E-V(x)

Click For Summary
SUMMARY

The discussion focuses on the WKB approximation in quantum mechanics, specifically addressing the relationship between the wavefunction's amplitude and the potential energy V(x) when E > V(x). The equation k(x) = √(2m(E - V(x)))/ħ indicates that k(x) is proportional to E - V(x), leading to an inverse relationship between wavelength λ and E - V(x). The amplitude of the wavefunction varies with V(x) due to its connection to momentum p = ħk, which is related to velocity v. A comprehensive resource for understanding the WKB approximation is the review by Berry and Mount.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly the WKB approximation.
  • Familiarity with wavefunctions and their properties in quantum systems.
  • Knowledge of momentum and its relationship to wavevector k.
  • Basic proficiency in LaTeX for mathematical expressions.
NEXT STEPS
  • Study the WKB approximation in detail, focusing on its applications in quantum mechanics.
  • Learn about the mathematical derivation of the wavefunction's amplitude in relation to potential energy.
  • Explore the implications of the eikonal approximation in wave mechanics.
  • Read the review by Berry and Mount for an in-depth understanding of the WKB method.
USEFUL FOR

Students and researchers in quantum mechanics, physicists interested in wavefunction behavior, and anyone studying the WKB approximation in theoretical physics.

curious.cat
Messages
6
Reaction score
0
Consider E>V(x). WKB states the wavefunction will remain sinusoidal with a slow variation of wavelength $ \lambda $ and amplitude given that V(x) varies slowly. From the equation \begin{equation}
k(x)=\frac{\sqrt{2m(E-V(x))}}{\hbar}
\end{equation}, I can see that the k(x) is directly proportional to E-V(x), implying that $ \lambda $ is inversely proportional to E-V(x). I cannot understand why the amplitude should change with a variation in V(x). I do know that if E-V(x) becomes negative then the wavefunction becomes exponentially decaying in which case the wavefunction is no longer a periodic function (hence, amplitudes and wavelengths no longer apply). What is the equation connecting amplitude with V(x)? I am stuck and unable to proceed any further. Sorry about the equation numbering. I am rather new to LATEX
 
Physics news on Phys.org
k(x) is only the first term in an expansion of the wavefunction into orders of ##\hbar##, the next order therm, called the eikonal, gives you the variation of the amplitude.
It should be obvious why the amplitude changes with k: ##p=\hbar k## is momentum and proportional to v. Already classically, the probability to find, say, a planet at a given point of its orbit when averaging over time is inversely proportional to v. But the amplitude of the wavefunction is the square root of this probability. Everything you ever want to know about the WKB approximation can be found in the review by Berry and Mount: http://iopscience.iop.org/article/1...678CE73A943EED846ECCF5898519449.ip-10-40-1-74
 
  • Like
Likes   Reactions: curious.cat
Thank you!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K