Uniform circular motion mass problem

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SUMMARY

The discussion focuses on a uniform circular motion problem involving a mass of 1.5 kg moving in a circle with a radius of 25 cm at a rate of 2 revolutions per second. The calculated tangential velocity is 3.14 m/s, the radial acceleration is 39.4 m/s², and the required centripetal force is 59 N. Key equations used include v = 2πR/T and F = ma, with the radius converted to meters for accurate calculations.

PREREQUISITES
  • Understanding of uniform circular motion principles
  • Familiarity with the equations of motion, specifically v = 2πR/T
  • Knowledge of centripetal force calculations
  • Ability to convert units, particularly from centimeters to meters
NEXT STEPS
  • Study the derivation of the centripetal force formula F = mv²/r
  • Learn about angular velocity and its relationship to linear velocity
  • Explore the effects of varying mass and radius on centripetal force
  • Investigate real-world applications of uniform circular motion in engineering
USEFUL FOR

Students studying physics, educators teaching circular motion concepts, and anyone interested in the dynamics of objects in circular paths.

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Homework Statement


A mass of 1.5 kg moves in a circle of radius 25 cm at 2 rev/s. calculate (a) the tangential velocity, (b) the acceleration, (c) the required centripetal force for the motion.
Answers:
A) 3.14 m/s
B) 39.4 m/s^2 radially inward
C) 59 N


Homework Equations


v=2piR/T


The Attempt at a Solution


(for part a)
V = 2 pi 25 / T
but what is T?

then i tried:
F = ma = mv^2/r
v^2=Fm/r
v= (the square root of)Fm/r
but I don't know what F is.
 
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I think I've got it!

V= 2 pi r / t
V= 2 pi .25 / .5
V=1.57/.5
V=3.14 m/s

r = .25, not 25, because it has to be in meters.
and t = .5 because if it takes 1 second to make 2 revolutions, it must take .5 seconds to make one revolution.

yay (:
 

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