Union or Intersection for f(x)=0 When x in A and B

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SUMMARY

The discussion centers on the logical implications of the function equation $f(x)=0$ for sets A and B. It is established that if $f(x)=0$ for all elements in set A and for all elements in set B, then it necessarily follows that $f(x)=0$ for all elements in the union of sets A and B, denoted as $A \cup B$. The conclusion is that the intersection of the sets does not apply in this context, as the property holds for the union.

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evinda
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Hello! (Wave)

When we have: $f(x)=0, \forall x \in A \wedge f(x)=0, \forall x \in B$, do we conclude that $f(x)=0, \forall x \in A \cap B$ or $f(x)=0, \forall x \in A \cup B$? (Thinking)
 
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Don't put a comma between $f(x)=0$ and $\forall x\in A$. Similarly, don't put a comma before "that".

If something holds for all $x\in A$ and all $x\in B$, then it holds for all $x\in A\cup B$.
 
Evgeny.Makarov said:
Don't put a comma between $f(x)=0$ and $\forall x\in A$. Similarly, don't put a comma before "that".

If something holds for all $x\in A$ and all $x\in B$, then it holds for all $x\in A\cup B$.

I see... Thank you very much! (Smile)
 

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