Unique Solution Exists to x^n=y: Real Analysis Proof

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SUMMARY

The discussion centers on proving the existence and uniqueness of a positive real number y such that y^n = x for x > 0 and n in the natural numbers. The hint provided involves considering y = 1 and utilizing the concept of least upper bounds (l.u.b.) in real analysis. Participants clarified the notation "u.b." as referring to "least upper bound," which is essential for understanding the proof structure. This foundational concept aids in establishing the uniqueness of the solution.

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  • Understanding of real analysis concepts, particularly least upper bounds (l.u.b.)
  • Familiarity with the properties of natural numbers (N)
  • Basic knowledge of exponentiation and its implications in real numbers
  • Experience with formal proof techniques in mathematics
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  • Study the concept of least upper bounds in real analysis
  • Explore proofs involving the existence and uniqueness of solutions in mathematical analysis
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Mathematics students, particularly those studying real analysis, and educators looking to deepen their understanding of proof techniques and the properties of real numbers.

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Homework Statement


Given x > 0 and n \in N, prove that there is a unique y > 0 s.t. y^n = x exists and is unique

Homework Equations


Hint is given: consider y = 1. u.b. \{s \in R : s^n < x\}

The Attempt at a Solution


I'm not used to this style of proof (real analysis I), help would be appreciated, thanks. BTW, what does "u.b." signify?
 
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It's actually l.u.b. with a letter "L" instead of a digit "1". It means "least upper bound. Does that help?
 
oh, now its clearer. thanks
 

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