MHB Can You Solve This Tricky Trigonometric Floor Function Equation?

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The discussion revolves around solving the equation involving the floor function and trigonometric functions: {sin(⌊x⌋)} + {cos(⌊x⌋)} = {tan(⌊x⌋)} for real solutions. Participants clarify that the notation {x} represents the fractional part of x, defined as x - ⌊x⌋. There is also a question about whether x is measured in radians or degrees, with confirmation that x is in radians. The thread emphasizes understanding the fractional part in the context of the equation. Overall, the focus is on finding real solutions to the given trigonometric equation.
anemone
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Solve $\{ \sin \lfloor x \rfloor \}+\{ \cos \lfloor x \rfloor \}=\{ \tan \lfloor x \rfloor \}$ for real solution(s).
 
x in radian or degree ?
 
Hi Kali, $x$ is in radian.
 
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anemone said:
Solve $\{ \sin \lfloor x \rfloor \}+\{ \cos \lfloor x \rfloor \}=\{ \tan \lfloor x \rfloor \}$ for real solution(s).
Sorry, but I'm a bit confused. I know what the floor function does but what does the {.} do?

-Dan
 
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Sorry Dan for not being clear in my question.(Blush)

{} means the fractional part of $x$, and defined by the formula $\{ x \}=x-\lfloor x \rfloor$.

Hope this clears it up!
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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