UP regarding value of a field and its rate of change

  • Thread starter Suwailem
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  • #1
Suwailem
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Main Question or Discussion Point

I am just a hobbyist and try to learn for myself.

I understand that the value of a field and its rate of change play the same role of position and momentum of a particle with respect to Uncertainty Principle, i.e. both pairs are conjugate variables. My question is: does the rate of change of a field extends to the negative domain, so that it could take negative values, or is it always non-negative?
 

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  • #2
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Derivative of a field can be negative and it often is negative. If it were always positive (or zero), the field value would be always and forever growing (or not changing).
 
  • #3
Suwailem
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Thank you mvp_plate.
 
  • #4
Suwailem
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If the momentum is always positive (or non-negative), then the analogy of momentum with rate of change will not be one to one?
 
  • #5
Nugatory
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If the momentum is always positive (or non-negative), then the analogy of momentum with rate of change will not be one to one?
Momentum is not always non-negative. Consider two bodies of equal mass moving in opposite directions: their momenta will be of equal magnitude but opposite sign, so the total momentum of the system is zero.
 
  • #6
Suwailem
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Momentum is not always non-negative. Consider two bodies of equal mass moving in opposite directions: their momenta will be of equal magnitude but opposite sign, so the total momentum of the system is zero.
Thank you Nugatory.
 

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