Upthrust in water with different gravity

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Homework Help Overview

The discussion revolves around the behavior of a cork floating in water when the system is transferred to an environment with a different gravitational acceleration. The original poster questions how the submerged proportion of the cork will change under reduced gravity and seeks reasons for their conclusion that it will become less submerged.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to reason through the relationship between gravity, buoyancy, and the submerged volume of the cork. They question whether the weight of the displaced water affects the upthrust force and if volume and density are the only factors involved.
  • Some participants clarify that changes in gravitational acceleration affect the weights of both the cork and the displaced water, which in turn influences the buoyancy force.
  • Others reiterate the principle that the buoyancy force is equal to the weight of the fluid displaced, suggesting that the floating position of the cork may remain unchanged despite the change in gravity.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of buoyancy and the effects of gravity. Some guidance has been provided regarding the relationship between buoyancy and displaced fluid weight, but no consensus has been reached on the original poster's question.

Contextual Notes

Participants are considering the implications of transferring the cork and water system to an environment with lower gravity, which raises questions about the assumptions regarding buoyancy and weight in different gravitational contexts.

Scarlet_pat
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Homework Statement




A small cork floats in water, exactly half submerged, on Earth. If the container,
water and cork were all transferred to a place where the acceleration due to
gravity is less than that on Earth, would the submerged proportion of the cork
be greater. stay the same or become less?


give 2 reasons for your answers

The Attempt at a Solution



The submerged proportion of the cork will become less.

Because the volume remains constant while the weight of the object changed due the different gravity.
the upthrust force will be greater than the force of the object exerted.

Question: is the answer correct? it is quite plausible because the weight of the water has also changed. Does it affect the upthrust force? or volume and destiny are the only elements which will affect the upthrust force of liquid.

thank you very much :)
 
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If the value of g changes, then it affects the weights of all things equally. That includes the weight of the water displaced by a given volume, which determines the magnitude of the buoyancy force.
 


the net upward buoyancy force is equal to the magnitude of the weight of fluid displaced by the body. and therefore... the floating object will remains at it's original position ... right ?
thanks for reply :)
 


Scarlet_pat said:
the net upward buoyancy force is equal to the magnitude of the weight of fluid displaced by the body. and therefore... the floating object will remains at it's original position ... right ?
thanks for reply :)

The magnitude of the buoyancy force is equal to the weight of the fluid displaced by the body, right.

The weights of the body and the water are both determined by the local g, which behaves as a simple proportionality constant for the underlying masses. The ratios and relationships that determine buoyancy effects remain the same.
 


gneill said:
The magnitude of the buoyancy force is equal to the weight of the fluid displaced by the body, right.

The weights of the body and the water are both determined by the local g, which behaves as a simple proportionality constant for the underlying masses. The ratios and relationships that determine buoyancy effects remain the same.

thanks for such sophisticated explanation :)
 

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