Help Solve Physics Problem: Rocket Acceleration in <60 mins

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Homework Help Overview

The discussion revolves around a physics problem involving a rocket launched with constant acceleration and a bolt that falls off after a specific time. Participants are tasked with determining the rocket's acceleration based on the time it takes for the bolt to hit the ground after detaching.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the rocket's acceleration and the displacement of the bolt. Some express uncertainty about how to set up the equations needed to solve the problem. Others attempt to derive the displacement equations and relate them to the time intervals involved.

Discussion Status

There are multiple approaches being explored, including numerical solutions and analytical methods. Some participants have shared their calculations and programming attempts, while others are seeking clarification on the reasoning behind the results presented.

Contextual Notes

Participants mention constraints such as time pressure to solve the problem and the context of upcoming tests where certain tools may not be allowed. There is also a reference to an earlier incorrect solution, indicating ongoing adjustments in understanding.

mattmaka
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Urgent help needed on physics problem!

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.40 s later.

What is the rocket's acceleration?

I have less than an hour to answer this online, please help.
 
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I have no idea how to relate the distances or anything. Any help in setting up equations would be great.
 
Ok I made a little mistake before. R is the rocket's acceleration so the displacement for the first 4 seconds is d0 = 0.5 * R * 4^2 = 8R. The velocity it gains during this time is equal to R*T = 4R

Now during the drop the displacement is given by d = d0 + v1*t + 0.5*(-g)*t^2

At t = 6.4 seconds d and d0 are equal. Subbing in some stuff and knowing that d = 0 after 6.4 seconds 0 = 8R + 4R*6.4 - 4.9*6.4^2. Solve for R.
 
Last edited by a moderator:
mattmaka said:
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.40 s later.

What is the rocket's acceleration?

I have less than an hour to answer this online, please help.
5.95 m/s^2
 
How did you get the answer tony?
 
Thaore0 said:
How did you get the answer tony?
I wrote a computer program, trying different values for a, until t = 10.4
Code:
Private Sub Command1_Click()
Dim a As Double, Vrocket As Double, Vbolt As Double, pRocket As Double, pBolt As Double
Dim t As Double, sstep As Double

sstep = 0.01
pRocket = 0
Vrocket = 0
a = 5.95

For t = 0 To 4 Step sstep
    Vrocket = Vrocket + a * sstep
    pRocket = pRocket + Vrocket
Next t

pBolt = pRocket
Vbolt = Vrocket
t = 4 + sstep

While pBolt > 0
    Vbolt = Vbolt - 9.81 * sstep
    pBolt = pBolt + Vbolt
    t = t + sstep
Wend
Text1.Text = t
End Sub
 
Sweet! Is that Visual Basic?
 
Thaore0 said:
Sweet! Is that Visual Basic?
Yes, VB 6.0. That's how I do the problems I can't quite understand. It's called a numerical solution. There are some problems where no analytical solution exists, and a numerical solution is necessary.

But I'm sure that an analytical solution exists for this problem, and I'm waiting to see if someone knows it. This is the type of problem I'm going to face in about 2 weeks. (And I'm not allowed to bring my laptop to tests :smile: )
 
Read my post above sorry I posted an incorrect solution before it's about 5.96.
 
  • #10
thanks for the help guys.
 
  • #11
mattmaka said:
thanks for the help guys.
Did you get it right? I imagine you're using an instant grading homework system?
 

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