MHB Use algebraic manipulation to prove the distributivity property

AI Thread Summary
The discussion focuses on proving the distributive property using algebraic manipulation with the equation x + yz = (x + y)(x + z). Participants attempt to expand the right side, leading to expressions involving terms like xx, xz, and xy. The confusion arises around simplifying these terms to match the left side of the equation, particularly in transitioning from x + xy + xz + yz to x + yz. Ultimately, the goal is to clarify the steps needed to demonstrate that both sides of the equation are equivalent, emphasizing the importance of proper algebraic manipulation. The conversation highlights the challenges in understanding the distributive rule in this context.
shamieh
Messages
538
Reaction score
0
Use algebraic manipulation to prove that x+yz=(x+y)(x+z) Note that this is
the distributive rule,

So I have:

(x + y)(x + z) = xx + xz + xy + zy
= x + xz + xy + zy
= x(1 + z + y) zy
=x * 1 + (z + y)(zy)
= x + ((zzy + yzz)
= x +y + z?


but i need x + yz... But I don't understand what is going on in the right side
 
Physics news on Phys.org
I don't understand what you are doing, either.

(x + y)(x + z) = (x + y)x + (x + y)z

= xx + yx + xz + yz = xx + xy + xz + yz (since xy = yx)

= x + xy + xz + yz (since xx = x)

= x(1 + y + z) + yz =...?
 
Back
Top