Use L'Hopital's Rule to relate to limit definition for e

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SUMMARY

The limit lim x→0+ (1 + x)^(1/x) can be evaluated using the limit definition of e, which states that lim n→∞(1 + 1/n)^n = e. By substituting x with 1/u, where u approaches infinity as x approaches 0, the limit transforms to lim 1/u→∞ (1 + 1/u)^(u) = e. This confirms that the limit evaluates to e, establishing a direct relationship between the two limits.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with L'Hopital's Rule
  • Knowledge of the exponential constant e
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the application of L'Hopital's Rule in evaluating limits
  • Explore the properties and applications of the exponential function e
  • Learn about the derivation of the limit definition of e
  • Investigate other forms of limits that converge to e
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Students and educators in calculus, mathematicians exploring limits, and anyone interested in the foundational concepts of exponential functions.

Painguy
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Homework Statement


It can be shown that
lim
n→∞(1 + 1/n)^n = e.
Use this limit to evaluate the limit below.

lim
x→0+ (1 + x)^(1/x)

Homework Equations




The Attempt at a Solution


So i guess what i need to do is try to get that limit in the form of the limit definition for e.

lim
x→0+ (1 + x)^(1/x)

x=1/u

since x-> 0 that means 1/u ->inf

lim
x→0+ (1 + 1/u)^(1/(1/u))

= lim
1/u→∞ (1 + 1/u)^(u) = e

I feel like my last 2 steps are wrong, but I am sure my answer is right.
 
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Painguy said:

Homework Statement


It can be shown that
lim
n→∞(1 + 1/n)^n = e.
Use this limit to evaluate the limit below.

lim
x→0+ (1 + x)^(1/x)

Homework Equations




The Attempt at a Solution


So i guess what i need to do is try to get that limit in the form of the limit definition for e.

lim
x→0+ (1 + x)^(1/x)

x=1/u

since x-> 0 that means 1/u ->inf

lim
x→0+ (1 + 1/u)^(1/(1/u))

= lim
1/u→∞ (1 + 1/u)^(u) = e

I feel like my last 2 steps are wrong, but I am sure my answer is right.
You have x = 1/u,

so if x → 0+, then so does 1/u → 0+.

What that implies is that u → +∞ .
 
SammyS said:
You have x = 1/u,

so if x → 0+, then so does 1/u → 0+.

What that implies is that u → +∞ .

That makes more sense. Thank you very much.
 

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