Use linear interpolation to estimate sin 36 using as your 'known' values 0 & 60?

[escobar147]

here is the answer:

36/60 = x/.8660

60x = .8660 x 36

60x = 31.176

x = .5196

however, where does the value: 0.8660 initially come from?

any help would be appreciated

 

[rcgldr]

however, where does the value: 0.8660 initially come from?

sin(60°) ~= 0.8660 (and sin(0°) = 0).

 

[escobar147]

sin(60°) ~= 0.8660 (and sin(0°) = 0).

thanks