Use mathematical induction to prove the following statements are true

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SUMMARY

The discussion focuses on using mathematical induction to prove the formula for the sum of squares of the first n odd numbers, specifically the equation 1^2 + 3^2 + 5^2 + ... + (2n-1)^2 = [n(4n-1)]/3 for n ≥ 1. Participants emphasize the importance of correctly substituting variables during the induction step, particularly using k and k+1 instead of mixing n and k. Errors in the initial attempts to prove the statement are identified, including incorrect substitutions and notation. The correct approach involves verifying the base case and ensuring proper variable consistency throughout the proof.

PREREQUISITES
  • Understanding of mathematical induction principles
  • Familiarity with sequences and series, particularly odd numbers
  • Basic algebraic manipulation skills
  • Knowledge of summation notation and its applications
NEXT STEPS
  • Study the principles of mathematical induction in depth
  • Practice proving other summation formulas using induction
  • Explore the concept of sequences and series in greater detail
  • Learn about common pitfalls in mathematical proofs and how to avoid them
USEFUL FOR

Students studying mathematics, particularly those focusing on algebra and proof techniques, as well as educators looking to enhance their teaching methods in mathematical induction.

Daaniyaal
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Homework Statement


Use mathematical induction to prove the following statements are true for n≥1

a) 1^2+3^2+5^2+...+(2n-1)^2= [n(4n-1)]/3

Homework Equations





The Attempt at a Solution


Attempt at showing for n+1 is true:

n[4(n+1-1)]/3+ 2[k+1-1)^2
 
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First off start by letting n=1 and check it. Then you can go to n+1.
 
Daaniyaal said:

Homework Statement


Use mathematical induction to prove the following statements are true for n≥1

a) 1^2+3^2+5^2+...+(2n-1)^2= [n(4n-1)]/3

Homework Equations





The Attempt at a Solution


Attempt at showing for n+1 is true:

n[4(n+1-1)]/3+ 2[k+1-1)^2
First, what you are trying to prove true is an equation, and you have not "=". It looks to me like this is the right side of n= k with the new term added- but there are several errors.
First, bcause the term on the left is to be the "old" sum, you should not have "n+1" in place of n in 4(n-1)/3 but you should have 4(k-1)/3, not n. Second, in the sum the last term is (2n-1)^2- that is all squared so replacing n with k+ 1 gives (2(k+1)+1)^2 NOT "2[k+1-1]^2".

Since you want to prove the original statement is true for all n, it is a good idea to use "k" and "k+1" for the induction step. But do not mix "k" and "n".
 
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