Using a MOSFET and comparator together as a switch

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Using a MOSFET and a comparator together can effectively manage solar charging by preventing overcharging of batteries. A standard voltage comparator can be paired with a 3-terminal voltage regulator to achieve the desired internal reference voltage of 5.5V. Implementing a voltage divider with two resistors can help generate this reference voltage. It's important to include hysteresis in the comparator's feedback to prevent noise-induced switching. Properly configuring these components will ensure the solar charger operates efficiently and safely.
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Hello all, I was advised to use a MOSFET and a comparator together in a solar charger that I am building to stop the solar panel from charging the batteries when full. Seems logical, right? The only problem is I've never used MOSFETs or comparators, so I'm not really sure how to. I need a comparator with an internal reference voltage of 5.5V and a MOSFET rated for 100 ma. I looked around and found a MOSFET but I couldn't find a comparator with an internal reference voltage... does anyone know where I could find one? And once I do find one how to hook it all up?
 
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You should use a standard voltage comparator along with a separate 3-terminal voltage regulator like the Motorola MC7806 (see
http://www.datasheetarchive.com/pdf-datasheets/Datasheets-21/DSA-405486.pdf
and use two resistors (voltage divider) to get 5.5 volts.
 
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Be sure to put a couple hundred millivolts of hysteresis into your positive feedback on the comparator, to avoid noise switching and buzzing.
 
You want to stop charging when the battery reaches a certain voltage? Just charge the battery with the output of a voltage regulator set at that cutoff voltage. It'll cut off the current when the battery voltage reaches the output voltage.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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