Using bond energies to calculate energy changes

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SUMMARY

This discussion focuses on calculating energy changes in chemical reactions using bond energies. The reactions analyzed include the formation of hydrogen peroxide (H2O2) and water (H2O) from hydrogen (H2) and oxygen (O2), as well as the formation of methanol (CH3OH) from hydrogen and carbon monoxide (CO). The calculations reveal that all three reactions are exothermic, with net energy changes of -498 kJ for the first two reactions. The importance of accurately identifying bond types and energies, such as distinguishing between C=O and C-O bonds, is emphasized for correct calculations.

PREREQUISITES
  • Understanding of bond energies and their values from a reference table.
  • Familiarity with chemical reaction types, specifically endothermic and exothermic reactions.
  • Ability to perform energy calculations involving bond breaking and bond formation.
  • Knowledge of Lewis structures for accurate representation of molecular bonds.
NEXT STEPS
  • Study the bond energies listed in a standard chemistry textbook, such as "Chemistry: The Central Science" by Brown et al.
  • Learn how to draw and interpret Lewis structures for various organic compounds.
  • Explore the concept of enthalpy changes in chemical reactions using Hess's Law.
  • Investigate the stability of reaction products and how it relates to exothermic and endothermic processes.
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical engineering or research who need to understand energy changes in chemical reactions.

bjoyful
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Homework Statement



Use the bond energies (in Table 4.2) to calculate the energy changes associated with each of these reactions. In each case indicate whether the overall reaction is endothermic or exothermic. Be sure to show your calculation work.

2. Homework Equations [/b

The Attempt at a Solution



A. H2(g) + O2(g) -----> H2O2(g) Answer: H2 is H-H (+436) and O2 is O=O (+498). Total energy in breaking bonds is 934 kJ. H2O2 is H-O=O-H (-467,-498,-467). Total in making bonds is -1432 kJ. Therefore, the net energy change is -498kJ, with the overall reaction being exothermic.

B. 2H2(g) + O2(g) -----> 2H2O(g) Answer: 2H2 is H-H (+436), H-H (+436). O2 is O=O (+498). Total energy in breaking bonds is +1370kJ. 2H20 is H-O-H (-467x2), H-O-H (-467x2). Total energy in making bonds is -1868kJ. Therefore, the net energy change is
-498kJ, with the overall reaction being exothermic.

C. 2H2(g) + CO(g) -----> CH3OH(g). Answer: H-H (+436), H-H (+436). CO is C=O (+1073). Total in breaking bonds is +1208. CH3OH is C-H (-416x3), C=O (-803), O-H (-467)

I find it strange that I came up with exothermic for all three of these...
 
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Why?
 
many more reactions are exothermic than endothermic. exothermic reaction tends to form more stable products, and hence are favoured by nature.
 
okay, that makes sense. I thought I had done my work right, but it seems usually there are examples of both things in such problems. Thanks for explaining that to me.
 
another question on this...did I do this correctly as far as how I broke it down: CH3OH is C-H (-416x3), C=O (-803), O-H (-467). I am doubing guessing myself!
 
draw the lewis structure. you will see that there are 3 C - H bonds (correct), 1 O - H bond (correct) but a C - O bond instead of C = O. the C - O bond is about 360 kJ.
 
I guess I totally drew that wrong:(Thanx for showing me the right way...
 

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