Using Creation and Annihilation Operators in a Fermionic 2-State System

  • Thread starter Thread starter Urvabara
  • Start date Start date
  • Tags Tags
    System
Click For Summary

Homework Help Overview

The discussion revolves around a fermionic system characterized by four states: |00⟩, |01⟩, |10⟩, and |11⟩. Participants are exploring the creation and annihilation operators associated with this system and how to compute their matrix elements.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to calculate the matrix elements of the annihilation operator f₁ and are questioning how to properly position these elements in a matrix. There are discussions about normalization constants and the implications of the number operator.

Discussion Status

Some participants have provided hints and corrections regarding the placement of matrix elements and the nature of the system, indicating a productive exchange of ideas. However, there is no explicit consensus on the final form of the operators or the understanding of the system's classification.

Contextual Notes

There is confusion regarding the classification of the system as a "two-state" versus a "four-state" system, with some participants suggesting it may be a "2-site" problem instead.

Urvabara
Messages
98
Reaction score
0

Homework Statement



A fermionic 2-state system is \left\{\left|00\right\rangle, \left|10\right\rangle, \left|01\right\rangle, \left|11\right\rangle\right\}, where
\left|ab\right\rangle = \left|a\right\rangle_{1}\left|b\right\rangle_{2} and \left\langle ab\left|cd\right\rangle = \delta_{ac}\delta_{bd}.

Homework Equations



What are the creation and annihilation operators f_{1}, f_{1}^{\dagger}, f_{2}, f_{2}^{\dagger} in this base?

The Attempt at a Solution



I just do not know, how to get started. I just cannot find the theory and I do not know how to use it in this problem anyway. Can you give me some hints? Please, do not give right away the correct answers/results, just the hints to get started.
 
Last edited:
Physics news on Phys.org
How would you find the matrix elements <ab|f|cd> of an operator f?
 
Gokul43201 said:
How would you find the matrix elements <ab|f|cd> of an operator f?

So, I tried to calculate the matrix elements of an annihilation operator f_{1}. There are 16 of them, I think. Is this correct?
<br /> \left\langle 00\left|f_{1}\left|10\right\rangle = \left\langle 00\left|00\right\rangle = \delta_{00}\delta_{00} = 1\cdot 1 = 1.<br />
<br /> \left\langle 00\left|f_{1}\left|01\right\rangle = 0.<br />
<br /> \left\langle 00\left|f_{1}\left|11\right\rangle = \left\langle 00\left|01\right\rangle = \delta_{00}\delta_{01} = 1\cdot 0 = 0.<br />
<br /> \left\langle 00\left|f_{1}\left|00\right\rangle = 0.<br />
<br /> \left\langle 10\left|f_{1}\left|10\right\rangle = \left\langle 10\left|00\right\rangle = \delta_{10}\delta_{00} = 0\cdot 1 = 0.<br />
<br /> \left\langle 10\left|f_{1}\left|01\right\rangle = 0.<br />
<br /> \left\langle 10\left|f_{1}\left|11\right\rangle = \left\langle 10\left|01\right\rangle = \delta_{10}\delta_{01} = 0\cdot 0 = 0.<br />
<br /> \left\langle 10\left|f_{1}\left|00\right\rangle = 0.<br />
<br /> \left\langle 01\left|f_{1}\left|10\right\rangle = \left\langle 01\left|00\right\rangle = \delta_{00}\delta_{10} = 1\cdot 0 = 0.<br />
<br /> \left\langle 01\left|f_{1}\left|01\right\rangle = 0.<br />
<br /> \left\langle 01\left|f_{1}\left|11\right\rangle = \left\langle 01\left|01\right\rangle = \delta_{00}\delta_{11} = 1\cdot 1 = 1.<br />
<br /> \left\langle 01\left|f_{1}\left|00\right\rangle = 0.<br />
<br /> \left\langle 11\left|f_{1}\left|10\right\rangle = \left\langle 11\left|00\right\rangle = \delta_{10}\delta_{10} = 0\cdot 0 = 0.<br />
<br /> \left\langle 11\left|f_{1}\left|01\right\rangle = 0.<br />
<br /> \left\langle 11\left|f_{1}\left|11\right\rangle = \left\langle 11\left|01\right\rangle = \delta_{10}\delta_{11} = 0\cdot 1 = 0.<br />
<br /> \left\langle 11\left|f_{1}\left|00\right\rangle = 0.<br />

So, <br /> f_{1} = <br /> \begin{pmatrix}<br /> 1 &amp; 0 &amp; 0 &amp; 0 \\<br /> 0 &amp; 0 &amp; 0 &amp; 0 \\<br /> 0 &amp; 0 &amp; 1 &amp; 0 \\<br /> 0 &amp; 0 &amp; 0 &amp; 0 \\<br /> \end{pmatrix}?<br />
 
You've determined the non-zero matrix elements correctly, but put them in the wrong positions. The row and column indices come from the left side of those equations. Also, you haven't determined possible normalization constants.

f_1|11 \rangle = c |01 \rangle

What is c?
 
Last edited:
Gokul43201 said:
You've determined the non-zero matrix elements correctly, but put them in the wrong positions. The row and column indices come from the left side of those equations.

So, something like this
f_{1} = \begin{pmatrix}0 &amp; 1 &amp; 0 &amp; 0 \\0 &amp; 0 &amp; 0 &amp; 0 \\0 &amp; 0 &amp; 0 &amp; 1 \\0 &amp; 0 &amp; 0 &amp; 0 \\\end{pmatrix}?

Gokul43201 said:
Also, you haven't determined possible normalization constants.
f_1|11 \rangle = c |01 \rangle
What is c?

Hmm. I have no idea. Can you give a hint?
 
Urvabara said:
So, something like this
f_{1} = \begin{pmatrix}0 &amp; 1 &amp; 0 &amp; 0 \\0 &amp; 0 &amp; 0 &amp; 0 \\0 &amp; 0 &amp; 0 &amp; 1 \\0 &amp; 0 &amp; 0 &amp; 0 \\\end{pmatrix}?
Yes, that looks better.

Hmm. I have no idea. Can you give a hint?
Have you come across the number operator (e.g., n_1=f_1^{\dagger}f_1)?
 
Hi and thanks!

Gokul43201 said:
Yes, that looks better.
Have you come across the number operator (e.g., n_1=f_1^{\dagger}f_1)?

Yes, I think so. It gives the number of particles in the ground state. Right?
 
Also, n.b., this is not a two-state system.
 
olgranpappy said:
Also, n.b., this is not a two-state system.

Hmm. It is not? Oh boy. This was a exam problem. I failed badly in that exam. :confused:
 
  • #10
well, there are four states, |00>, |01>, |10>, |11>... So it's a four-state system.
 
  • #11
...two times two-states.
 
  • #12
I think the original question may have called it a "2-site" problem.
 

Similar threads

Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K