Using exponents and logarithms to calculute pH

[interhacker]

Homework Statement

If a solution containing a heavy concentration of hydrogen ions(i.e., a strong
acid) is diluted with an equal volume of water, by approximately how much is its
pH changed? (Express (pH)_diluted in terms of (pH)_original.)

Homework Equations

I think the question requires the equation defining pH:
pH = \log[H+]

The Attempt at a Solution

According to the document, the answer is supposed to be:

pH_{dilute} = pH_{original} + \log 2

 

[SteamKing]

If the concentration of H+ ions in the original (undiluted) solution is [H+] and you add approximately an equal amount of H+ ions by diluting the original solution, what is the total concentration of H+ ions in the dilute solution?

 

[symbolipoint]

interhacker,
pH means negative of the logarithm of hydrogen ion concentration; you were missing the negative sign.
pH = -log[H⁺]

If you just double the volume to make the dilution, this is only a fraction of a pH unit change. The concentration change must be up or down by a factor of 10 for a change of pH of one unit.

 

[epenguin]

He must have made another mistake that canceled out the first one and made the answer right!