Using Natural Logarithms to solve for x

[adillhoff]

Homework Statement

Use Natural Logarithms to solve for x in terms of y

y = \frac{e^{10x}+e^{-10x}}{e^{10x}-e^{-10x}}

Homework Equations

I am not too sure.

The Attempt at a Solution

I multiplied both sides by the denominator first.
Then I multiply by an LCD of e^{10x}
I end up with y(e^{20x})-y = (e^{20x})+1

EDIT: I don't really know where to go from here. Any direction would be greatly appreciated.

 

[micromass]

From were you ended up, you could proceed by putting all terms of the form e^{20x} to one side of the equation. Then factor it out and take the logarithm.

 

[adillhoff]

From were you ended up, you could proceed by putting all terms of the form e^{20x} to one side of the equation. Then factor it out and take the logarithm.

Absolutely. Thank you so much for the help. I ended up with

x=\frac{ln\frac{y+1}{y-1}}{20}