Prove arcsin x for its logarithm form

In summary, the logarithm form of arcsin x is ln[(√(1-x^2) + x)/√(1-x^2)]. It can be proven using the definition of inverse trigonometric functions and properties of logarithms. The domain of the logarithm form of arcsin x is -1 ≤ x ≤ 1 and it can be simplified using properties of logarithms. This form is commonly used in calculus to solve integrals involving inverse trigonometric functions.
  • #1
ichabodgrant
49
0

Homework Statement


Given sin x = (eix - e-ix) / 2i,
I want to prove that

arcsin x = -i ln(ix + √1 - x2)

Homework Equations


I know about the Euler's formula and complex number. But I have never learned about complex logarithms.

The Attempt at a Solution


I try to use x = sin y. But it seems not working. How to show that relation?
 
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  • #2
Why not try working it backward? Take the arcsin x and substitute it into the first equation for x.
 

1. What is the logarithm form of arcsin x?

The logarithm form of arcsin x is ln[(√(1-x^2) + x)/√(1-x^2)].

2. How do you prove the logarithm form of arcsin x?

To prove the logarithm form of arcsin x, you can use the definition of inverse trigonometric functions and properties of logarithms.

3. What is the domain of the logarithm form of arcsin x?

The domain of the logarithm form of arcsin x is -1 ≤ x ≤ 1.

4. Can the logarithm form of arcsin x be simplified?

Yes, the logarithm form of arcsin x can be simplified by using properties of logarithms such as combining logarithms and using the power rule.

5. How is the logarithm form of arcsin x used in calculus?

The logarithm form of arcsin x is often used in calculus to solve integrals involving inverse trigonometric functions.

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