Using potential energy graph, find particle turning point

[isukatphysics69]

Homework Statement

Homework Equations

E_mec - PE = KE

The Attempt at a Solution

When particle starts at x = 4 KE = .5(.25)(225) = 28.125
Energy of system = 28.125
I don't have anything with position here so i am unsure how to find what position that the energy will be equal to the E_mec and turn the particle around

 

[isukatphysics69]

I think i need to use force here and force is dPE(X)/dx

 

[haruspex]

KE = .5(.25)(225)

Check the mass.

how to find what position that the energy will be equal to the Emec

That's what the graph is for.

 

[isukatphysics69]

yes i solved it i should have marked solved i am not careful i am overwhelmed i have final exam Tuesday and a million physics homeworks and presentations and stuff omg