1. The problem statement, all variables and given/known data A 1kg particle is in a potential given in joules by U(x)=3x2+4x-5, where x is in metres. The particle is initially at position x=1m and moving with velocity v=4m/s in the +x direction. Find the position when the particle first comes to rest. 2. Relevant equations dKe = Kf-Ki , Kf=0 Ke=-1/2mvi^2 F=ma w=F x d 3. The attempt at a solution U'(x) = 6x+4 Force at 1m = 10N Ke=-1/2(1kg)(4)^2 = -8J -8=10xd d=-0.8m d=xf-xi -0.8=xf-1 xf=0.2m However this was wrong. i also tried using several different methods but they were all wrong .. Help would be appreciated !!