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## Homework Statement

A, B, C and D are celebrating their joint birthdays and find

that their ages add up to exactly 100 years. The sum of A's and

D's ages equals the sum of B and C, while the difference between

the ages of A and D is twice C's age. Finally when D is as old

as A is now, C will be twice as old as B is now.

Given that A is older than D, how old are the four of them?

## Homework Equations

I constructed the following but I am unsure if they are correct, and where I would go from there?

a+b+c+d = 100

a+d = b+c

a-d = 2c

a > d

when... d = a

2c = b

Any help greatly appreciated, thanks