V(volt)/A(angstrom) to W(watt)/cm2 (centimeter square)?

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SUMMARY

The discussion centers on the conversion of V(volt)/A(angstrom) to W(watt)/cm² (centimeter square) as presented in the paper "Modifying the Interlayer Interaction in Layered Materials with an Intense IR Laser." The conversion involves calculating intensity using the formula I = (1/2) * ε₀ * c * E², where ε₀ is the permittivity of free space, c is the speed of light, and E is the electric field strength. This method provides a systematic approach to derive intensity from voltage and current measurements in layered materials.

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  • Familiarity with physical constants such as permittivity of free space (ε₀) and the speed of light (c).
  • Basic knowledge of intensity calculations in physics.
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masyousaf1
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Dear all

I am reading one paper and confused how authors converted V(volt)/A(angstrom) to W(watt)/cm2 (sentimeter square). The article entitled

''Modifying the Interlayer Interaction in Layered Materials with an Intense IR Laser''
Associated link is
http://journals.aps.org/prl/abstract/10.1103/PhysRevLett.114.116102
Specific Text of this paper is also attached as a screen shot.

Many thanks
Best wishes
Masood
 

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The intensity will be the average of the square of the field, with proper physical constants. Try
$$
I = \frac{1}{2} \epsilon_0 c E^2
$$