V(volt)/A(angstrom) to W(watt)/cm2 (centimeter square)?

  • Context: Graduate 
  • Thread starter Thread starter masyousaf1
  • Start date Start date
  • Tags Tags
    Square
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
Sign up Log in
1 reply · 3K views
masyousaf1
Messages
26
Reaction score
0
Dear all

I am reading one paper and confused how authors converted V(volt)/A(angstrom) to W(watt)/cm2 (sentimeter square). The article entitled

''Modifying the Interlayer Interaction in Layered Materials with an Intense IR Laser''
Associated link is
http://journals.aps.org/prl/abstract/10.1103/PhysRevLett.114.116102
Specific Text of this paper is also attached as a screen shot.

Many thanks
Best wishes
Masood
 

Attachments

Discussion

Physics news on Phys.org
The intensity will be the average of the square of the field, with proper physical constants. Try
$$
I = \frac{1}{2} \epsilon_0 c E^2
$$