Vaidity of rotational formulae for variable acceleration

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SUMMARY

The discussion centers on the validity of rotational formulas under variable angular acceleration. The formulas v = rω and K = 0.5Iω² are confirmed as valid for any instantaneous conditions, while ω = ω₀ + αt is invalid due to its reliance on constant acceleration. The formulas atan = rα and arad = rω² are also validated, as they account for the non-linear nature of angular acceleration. The reasoning provided emphasizes the importance of understanding the relationship between linear and angular motion in rotational dynamics.

PREREQUISITES
  • Understanding of rotational kinematics and dynamics
  • Familiarity with angular acceleration concepts
  • Knowledge of the relationship between linear and angular velocity
  • Basic grasp of energy equations in rotational motion
NEXT STEPS
  • Study the derivation and applications of the formula v = rω in variable acceleration contexts
  • Explore the implications of non-constant angular acceleration on rotational motion
  • Learn about the relationship between tangential and radial acceleration in rigid body dynamics
  • Investigate the energy conservation principles in rotational systems, particularly K = 0.5Iω²
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Students of physics, mechanical engineers, and anyone involved in the study of rotational dynamics and kinematics will benefit from this discussion.

spaghetti3451
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Homework Statement



Which of the following formulas is valid if the angular acceleration of an object is not constant? Explain your reasoning in each case.

(a) v = rω;
(b) atan = r[itex]\alpha[/itex];
(c) ω = ω0 + [itex]\alpha[/itex]t;
(d) arad = rω2;
(e) K = 0.5Iω2.

Homework Equations



The Attempt at a Solution



(a) v = rω is derived from s = r[itex]\theta[/itex], where s is the arc length of the circular path, r is the radius and [itex]\theta[/itex] is the angular displacement. s = r[itex]\theta[/itex] is valid for each instant of time, whether the angular acceleration is constant or not, so v = rω is valid for variable angular acceleration.

(b) Don't know!

(c) Not valid as the assumption of constant acceleration leads to the formula.

(d) Don't know!

(e) The formula follows from the combination of K = 0.5mv2 and v = rω. v = rω is valid for any acceleration, so K = 0.5Iω2 is valid as well.

Any comments would be wel appreciated!
 
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You are saying that a and e work for a particular instant and c is a kinematic equation...

ω(t) ≠ ω0 + α(t)t ... would be correct.

For b and d you have presumably rejected the kind of argument you used at a. Why is that.
 
(b) atan = [itex]\frac{dv}{dt}[/itex] = [itex]\frac{d(rω)}{dt}[/itex] = r[itex]\alpha[/itex]. In other words, the tangential component of the linear acceleration of a particle within a rigid body is the rate of change of the linear speed of the particle. The linear speed depends on the angular speed of the body. In the formula, the angular speed is assumed to be variable (i.e. a function of time). Moreover, it is not constrained to be linear in time. This implies that the angular acceleration is a function of time. So, (b) is valid for variable acceleration.

(d) arad = [itex]\frac{v<sup>2</sup>}{r}[/itex] = ω2r. In other words, the radial component of the linear acceleration of a particle within a rigid body depends on the linear speed of the particle. The linear speed is a function of the angular speed of the particle. The angular speed is not constrained to be linear in time. This implies that the angular acceleration is a function of time. So, (d) is valid for variable acceleration.

(a) and (e) also do not constrain the angular speed to be linear in time. So, the angular acceleration is a function of time, i.e. those formulae are valid for variable acceleration.

I think this argument is much better than my previous one, because although (a) and (e) are valid for each instant of time, that doesn't hint on any constraint on ω.

Any comments would be greatly appreciated.
 

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