Vector Addition and Subtraction Questions

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SUMMARY

The discussion focuses on calculating the vector addition and subtraction of two vectors, A and B. Vector A has a magnitude of 7.90 units at an angle of 43.0° from the positive x-axis, while Vector B has a magnitude of 8.00 units directed along the negative x-axis. The participants detail the process of finding the x and y components of each vector and provide formulas for determining the resultant magnitudes and angles. Key calculations involve using trigonometric functions and the Pythagorean theorem to derive the final results.

PREREQUISITES
  • Understanding of vector components and trigonometry
  • Familiarity with the Pythagorean theorem
  • Knowledge of angle measurement in degrees
  • Ability to interpret vector direction and quadrant placement
NEXT STEPS
  • Learn how to calculate vector magnitudes using the formula |Vector| = √(X-component² + Y-component²)
  • Study the concept of vector direction using the tangent function: tan(θ) = Y-component / X-component
  • Explore graphical methods for vector addition and subtraction
  • Investigate the use of software tools for vector calculations, such as GeoGebra or MATLAB
USEFUL FOR

Students studying physics or mathematics, educators teaching vector analysis, and anyone interested in mastering vector operations in two-dimensional space.

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Vector A has a magnitude of 7.90 units and makes an angle of 43.0° counter-clockwise from the positive x-axis. Vector B has a magnitude of 8.00 units and is directed along the negative x-axis.

(a) Find the vector sum vector A + vector B .
Magnitude of vector A + vector B = ? units
Direction of vector A + vector B : ?° counterclockwise from +x-axis

(b) Find the vector difference vector A - vector B .
Magnitude of vector A - vector B : ? units
Direction of vector A - vector B : ?° counterclockwise from +x-axis

My attempt:
Ok, so I find the x and y components of vector A and B which is...
Ax=7.9 cos 43 = 5.778
Ay=7.9 sin 43 = 5.388

Bx=-8
By= 0

Now...I'm not sure what to do next?
 
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Add the x,y components together to get the components of your result in part a).

Make Vector components of B negative and then add the components together as before for part b).

To figure magnitudes
|Vector|2 = = X-component2 + Y-component2

To figure angle Y-Component/X-component = tanθ
(Make a drawing to be sure you have the angle in the correct quadrant.)
 
Got it. Awesome. Thanks.
 

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