CatSails
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Hi, I'm working through Schutz's intro to GR on my own, and I'm trying to do problems as I go to make sure it sinks in. I've encountered a bump in chapter 5, though. I don't think this is a tough problem at all, I think it's just throwing me off because x and y are coordinates as well as variables, if you know what I mean.
Hopefully my latex tags work!
Let [tex]f= x^2 +y^2 + 2xy[/tex]
[tex]V \rightarrow (x^2 +3y, y^2+3x)[/tex]
[tex]W \rightarrow (1,1)[/tex]
So, among other things, I have to express f as a function of r and theta, and find the components of V and W in the r, theta basis. I thought I knew what I was doing, but the new components of my V vector are pretty ugly, which always makes me suspicious.
[tex]x^2 + y^2 = r^2[/tex]
[tex]x = rcos\theta[/tex]
[tex]y=rsin\theta[/tex]
[tex]V^{\alpha '} = \Lambda^{\alpha '}_{\beta} V^{\alpha}[/tex]
Well, I'm pretty sure f is just [tex]f(r, \theta) = r^2 + 2r^2\cos\theta[/tex],
I'd rather not write out the matrix equation, but using the equation above for the transformation of vector components, and writing out V in r and theta as [tex]V \rightarrow (r^2\cos^2\theta +3r\sin\theta, r^2\sin^2\theta +3r\cos\theta)[/tex], and I've calculated the transformation matrix between cartesian and polar to have components from left to right, top to bottom, of [tex]\cos\theta, \sin\theta, -\sin\theta /r, \cos\theta/r[/tex], I get pretty ugly vector components for the new coordinate system (complete with things that don't simplify much, like cos^3 + sin^3, etc).
Does it look like I'm doing it right? Completely wrong matrix?
Thanks.
Homework Statement
Hopefully my latex tags work!
Let [tex]f= x^2 +y^2 + 2xy[/tex]
[tex]V \rightarrow (x^2 +3y, y^2+3x)[/tex]
[tex]W \rightarrow (1,1)[/tex]
So, among other things, I have to express f as a function of r and theta, and find the components of V and W in the r, theta basis. I thought I knew what I was doing, but the new components of my V vector are pretty ugly, which always makes me suspicious.
Homework Equations
[tex]x^2 + y^2 = r^2[/tex]
[tex]x = rcos\theta[/tex]
[tex]y=rsin\theta[/tex]
[tex]V^{\alpha '} = \Lambda^{\alpha '}_{\beta} V^{\alpha}[/tex]
The Attempt at a Solution
Well, I'm pretty sure f is just [tex]f(r, \theta) = r^2 + 2r^2\cos\theta[/tex],
I'd rather not write out the matrix equation, but using the equation above for the transformation of vector components, and writing out V in r and theta as [tex]V \rightarrow (r^2\cos^2\theta +3r\sin\theta, r^2\sin^2\theta +3r\cos\theta)[/tex], and I've calculated the transformation matrix between cartesian and polar to have components from left to right, top to bottom, of [tex]\cos\theta, \sin\theta, -\sin\theta /r, \cos\theta/r[/tex], I get pretty ugly vector components for the new coordinate system (complete with things that don't simplify much, like cos^3 + sin^3, etc).
Does it look like I'm doing it right? Completely wrong matrix?
Thanks.