Vector image on another vector

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Discussion Overview

The discussion revolves around the mathematical representation of a vector image of one vector (A) on another vector (B). Participants explore the definitions and relationships between these vectors, particularly in the context of vector notation and operations.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion regarding the distinction between vector A and its length, suggesting that A is treated as a scalar in their context.
  • Another participant clarifies that both A and |A| represent the length of vector A, indicating a common simplification in electromagnetic literature.
  • A suggestion is made to maintain consistency in notation, advising against switching between upper and lower case letters for vectors.
  • Concerns are raised about the mathematical operations being performed, specifically the dot product of vectors A and B, which leads to a scalar, and the subsequent operation involving that scalar and vector B.
  • A later reply indicates that the image of vector A on vector B is indeed a vector, emphasizing the need to define its direction in the equation.

Areas of Agreement / Disagreement

Participants express differing views on the treatment of vector A and its length, as well as the appropriate mathematical operations involving vectors A and B. The discussion remains unresolved regarding the best approach to represent the vector image.

Contextual Notes

There are limitations in the clarity of definitions and notation, as well as unresolved mathematical steps regarding the operations performed on the vectors.

baby_1
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Hello
I want to demonstrate a equation of Vector image on another vector (A on B)
gif.latex?A_{B}=\frac{(\bar{A}.\bar{B}).\bar{B}}{|B|^{2}}.gif

So i go this steps
gif.gif

and as we know
gif.gif

so change the equation
a}_{B}|Cos\Theta%20_{AB}=\bar{A}.\hat{a}_{B}=|\bar{A}|.\hat{a}_{B}.\hat{a}_{B}=\frac{(A.\bar{B}).gif

but in my equation A is (vector scale) not a (Vector)!
what is my problem?
 
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You have [itex]\overline{A}[/itex], [itex]A[/itex], and [itex]\left|\overline{A}\right|[/itex]. I understand that [itex]\overline{A}[/itex] is a vector and that [itex]\left|\overline{A}\right|[/itex] is its length but what is [itex]A[/itex]?
 
Thanks for your replay
A and |A| both of them are length of A vector (in electromagnetic books we assume that A=|A| for easy to write)
 
Then pick one and stick with it. Similarly, don't swap between upper and lower case.
 
I rewrite the Steps.
main formula:
gif.latex?A_{B}=\frac{%28\bar{A}.\bar{B}%29.\bar{B}}{|B|^{2}}.gif


steps:
gif.gif

as we know
gif.gif

and
gif.latex?\bar{A}.gif

so
heta%20_{AB}=\bar{A}.\hat{a}_{B}=|\bar{A}|.\hat{a}_{B}.\hat{a}_{B}=\frac{%28|\bar{A}|.\bar{B}%29.gif


but in my equation |A| is (vector length) not a (Vector)!
what is my problem?
 
Oh Baby,

What are you doing? You are taking the dot product of vector A and vector B which results in a scalar. Then you are taking the dot product of that scalar with vector B. That makes no sense.

I think you want the dot product of vector A and vector B/|B|. B/|B| is the unit vector in the B direction.

Ratch
 
Thanks friends
i found my probelm
Image of Vector of A on B is a Vector and we should define the direct of it when write the image equation
gif.latex?A_{B}=ACos\Theta%20_{AB}.gif
 

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