Vector Spaces: A Comparison of Two Bases in V3(R)

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SUMMARY

The discussion confirms that both sets A = {(0,2,2)^T, (1,0,1)^T, (1,2,1)^T} and B = {(1,2,0)^T, (2,0,1)^T, (2,2,0)^T} are bases of V3(R). The participants establish that these sets span V3(R) and are linearly independent, adhering to the definitions of span and basis in vector spaces. Therefore, both sets qualify as bases for the three-dimensional vector space over the reals.

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  • Understanding of vector spaces and their properties
  • Knowledge of linear independence and spanning sets
  • Familiarity with R^3 and its geometric interpretation
  • Basic concepts of linear algebra, including bases and dimensions
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ashnicholls
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Are these two sets:

A = {(0,2,2)^T, (1,0,1)^T, (1,2,1)^T}

B= {(1,2,0)^T, (2,0,1)^T, (2,2,0)^T}

Bases of V3(R)

I have found equations that show that they span V3(R)

And that both set are linearly independent.

So am I right in saying that they are both bases of V3(R).

Cheers Ash
 
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If you have three vectors in R^3 that span, then they must be linearly independent, and if you have three linearly independent vectors in R^3 then they must span. That follows from the definition of span and basis.
 

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