Vector subspace and linear transformation

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SUMMARY

The discussion focuses on the vector subspace X defined as X = {(x1, x2, x2 − x1, 3x2): x1, x2 ∈ R} and the linear transformation f(x1, x2, x2 − x1, 3x2) = (x1, x1, 0, 3x1). Key conclusions include that a basis for X consists of the vectors (1, 1, 0, 3) and (1, 2, 1, 6), resulting in a dimension of 2. The kernel of f is identified as ker f = {0}, and the image of f is the entire space X. The transformation f is not a bijection, and a diagonal matrix representation for f remains to be determined.

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X ={(x1,x2,x2 −x1,3x2):x1,x2 ∈R}
f(x1,x2,x2 −x1,3x2)=(x1,x1,0,3x1)
1. Find a basis for X.
2. Find dim X.
3. Find ker f and I am f
4. Find bases for ker f and I am f
5. Is f a bijection? Why?
6. Find a diagonal matrix for f.

My attempt:
1. (1, 1, 0, 3) and (1, 2, 1, 6)
2. Dim X = 2
3. Ker f = 0, I am f = X
4. (0,0,0,0)
5. I guess no, but do not know how to explain
6. No idea
 
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