Vector Triple Product: Simplification Possible?

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SUMMARY

The discussion centers on the simplification of the triple vector product defined as $\mathbf{b}\times(\mathbf{b}\times\mathbf{c}) = (\mathbf{b}\cdot\mathbf{c})\mathbf{b} - b^2\mathbf{c}$. Participants conclude that further simplification is not possible without additional information about the vectors $\mathbf{b}$ and $\mathbf{c}$. It is noted that the basis $\{\mathbf{b},\mathbf{b}\times\mathbf{c},\mathbf{b}\times(\mathbf{b}\times\mathbf{c})\}$ forms an orthogonal set, which relates to the Gram-Schmidt orthogonalization algorithm.

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Dustinsfl
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Given the basis $\{\mathbf{b},\mathbf{c},\mathbf{b}\times\mathbf{c}\}$.
We define the triple vector product as
$$
\mathbf{b}\times(\mathbf{b}\times\mathbf{c}) = (\mathbf{b}\cdot\mathbf{c})\mathbf{b} - b^2\mathbf{c}
$$
Can this be simplified further? We don't know if b and c are orthogonal just that they are linearly independent.
 
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Re: basic vector question

I don't think you can simplify further.
 
Re: basic vector question

dwsmith said:
Given the basis $\{\mathbf{b},\mathbf{c},\mathbf{b}\times\mathbf{c}\}$.
We define the triple vector product as
$$
\mathbf{b}\times(\mathbf{b}\times\mathbf{c}) = (\mathbf{b}\cdot\mathbf{c})\mathbf{b} - b^2\mathbf{c}
$$
Can this be simplified further? We don't know if b and c are orthogonal just that they are linearly independent.

Nope.
Note that $\{\mathbf{b},\mathbf{b}\times\mathbf{c},\mathbf{b}\times(\mathbf{b}\times\mathbf{c})\}$ is an orthogonal basis.
Effectively you are looking at the Gram-Schmidt orthogonalization algorithm.
 

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