Charge q1 = +8.36 μC is fixed at the origin and charge q2 = -4.28μC is fixed on the +x-axis, 0.371m from the origin.
(a) Find the direction and magnitude of the electric field at a point P that has coordinates (0.466, 0.466) m.
(b) Find the direction and magnitude of the force on a -2.00 μC charge placed at the point P. (Please state the direction as an angle measured counterclockwise from the positive x-axis.)
E = Kq/r^2
The Attempt at a Solution
Find θ1 = atan(0.466/0.466) = 45 degrees
θ2 = atan(0.466/0.095) = 78.48 degrees
I figured you just add the two vectors. For some reason I dont know how to... What is confusing me is that a can't use -4.28μC, for example, as the actual value. I think I need to use E=kq/r2 Here's what the diagram looks like
I really appreciate any help
I got the first part. It is attached
Would the second part just be F=Eq?
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