Velocity and kinetic energy of moving block

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SUMMARY

The discussion centers on calculating the velocity and kinetic energy of a 10 kg block subjected to multiple forces. The block experiences vertical forces of 50N each and horizontal forces of 20N and 50N. By applying Newton's Second Law, the resultant force can be determined, allowing for the calculation of final velocity after 5 seconds. The kinetic energy can then be computed using the formula KE = 0.5 * m * v^2, where m is mass and v is final velocity.

PREREQUISITES
  • Newton's Second Law of Motion
  • Basic understanding of force and motion
  • Kinetic Energy formula (KE = 0.5 * m * v^2)
  • Vector addition of forces
NEXT STEPS
  • Study the application of Newton's Second Law in various scenarios
  • Learn about vector addition and its importance in physics
  • Explore the concept of resultant forces in multi-force systems
  • Review examples of kinetic energy calculations in different contexts
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Physics students, educators, and anyone interested in understanding the dynamics of motion and energy calculations in mechanics.

lbcc
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Originally Posted by lbcc
okay,
so there's a 10 kg block with four different forces acting upon it:
vertical forces of 50N each
and horizontal forces of 20N and 50N.

After 5 seconds, how fast is this block moving?
and what is the Kinetic Energy of the block after 5 seconds?

if you could give me the equations I would use to figure these out that would be great..
 
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Ok, you have two horizontal forces (I guess they point in opposite directions). From that you can get the resultant force and then use Newtons 2nd law. Knowing initial velocity (I assume the block starts at rest) and the time you can find out the final velocity. And surely you know the equation for kinetic energy?
 

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